Bear with my working out lol,
8x3 = 24in^2
9x12 = 108in^2
6x7 = 42in^2
(11x4) / 2 = 22in^2
Total = 196in^2
Try that, I couldn’t tell where the tip on the triangle fell at. So it could be wrong but that is what I got and what I would put :)
Answer:
I belive the answer is A
Step-by-step explanation:
So any answer with 22t would make sense, so you have A and C. In C though, it is subtracting 22, but since 6195 is the total it would have to include the 22 so it is A.
A) Find KM∠KEM is a right angle hence ΔKEM is a right angled triangle Using Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides we can answer the
KM² = KE² + ME²KM² = 8² + (3√5)² = 64 + 9x5KM = √109KM = 10.44
b)Find LMThe ratio of LM:KN is 3:5 hence if we take the length of one unit as xlength of LM is 3xand the length of KN is 5x ∠K and ∠N are equal making it a isosceles trapezoid. A line from L that cuts KN perpendicularly at D makes KE = DN
KN = LM + 2x 2x = KE + DN2x = 8+8x = 8LM = 3x = 3*8 = 24
c)Find KN Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have the same height ME = LD.
∠K = ∠N Hence KE = DN the distance ED = LMhence KN = KE + ED + DN since ED = LM = 24and KE + DN = 16KN = 16 + 24 = 40
d)Find area KLMNArea of trapezium can be calculated using the formula below Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)substituting values into the general equationArea = 1/2 * ME * (KN+ LM) = 1/2 * 3√5 * (40 + 24) = 1/2 * 3√5 * 64 = 3 x 2.23 * 32 = 214.66 units²
Answer:

Step-by-step explanation:
9 pencils cost $7.74
6 pencils cost x
The ratios are

According to the alternendo property,

Answer:
C
Step-by-step explanation:
∠ AFD = ∠ AFB + ∠ BFC + ∠ CFD
The 3 angles form a straight angle and sum to 180°, that is
4x + 5 + 6x + 3 + 5x + 7 = 180, that is
15x + 15 = 180 ( subtract 15 from both sides )
15x = 165 ( divide both sides by 15 )
x = 11
∠ CFD = 5x + 7 = 5(11) + 7 = 55 + 7 = 62°, thus
∠ AFE = ∠ CFD = 62° ( vertical angles are congruent )