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telo118 [61]
3 years ago
6

Shannon's scooter has a piece of tape stuck to the tire. If the tire has a diameter of 18 inches, how far does the piece of tape

travel in 72° of rotation?
Mathematics
2 answers:
saveliy_v [14]3 years ago
5 0

Answer:

11.31 inches

Step-by-step explanation:

The tape will move along the circumference of the wheel, so first the circumference should be calculated using the radius, which is half of the diameter:

C=2\pi r\\C=2\pi 9\\C=56.55 inches

If the tape would go all the way around, it would travel for 360°. For this scenario it only travels a fraction of that:

d=\frac{72}{360}*56.55\\d=11.31inches

maria [59]3 years ago
3 0

Shannon's scooter has a piece of tape stuck to the tire. If the tire has a diameter of 18 inches, the distance traveled by the piece of tape in 72 degree rotaion can be solve using:

S= ra, where s is the distance traveled, r is the radius and a is the angle in radians

s = (18in/2)(72 degree)(pi/180 degrees) = 11.31 in.

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Step-by-step explanation:

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A cylinder. The diameter of the base is 5 feet and the height of the cylinder is 12 feet.
MaRussiya [10]

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235.5 ft³

Step-by-step explanation:

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6 0
3 years ago
A car needs 54 liter petrol for running 648km how many km will it go with 10 liter petrol​
AlexFokin [52]

Answer:

The answer is 120km.

Step-by-step explanation:

We can set up the proportion that for every 54 liters, the car will go 648km.

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4 0
4 years ago
Which expression is equivalent to ^3√x^5y?<br>a)x5/3<br>b)x5/3y1/3<br>c)x3/5 y<br>d)x3/5 y3​
Illusion [34]

Answer:

(x^5y)^{\frac{1}{3}}= x^{\frac{5}{3}} \times y^{\frac{1}{3}}

Step-by-step explanation:

We are given our expression as

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The property of exponent says that

\sqrt[n]{x} =x^{\frac{1}{n}}

Hence

\sqrt[3]{x^5y}= (x^5y)^{\frac{1}{3}}

Another property says

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(x^5y)^{\frac{1}{3}}= x^{\frac{5}{3}} \times y^{\frac{1}{3}}

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7 0
3 years ago
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