Since opposite angles and sides are equal, then the quadrilateral ABCD is a parallelogram.
Given that, ABCD is a quadrilateral, segment AB is congruent to segment CD, ∠1 is congruent to ∠2.
We need to prove that ABCD is a parallelogram.
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How to prove a given quadrilateral is a parallelogram?</h3>
If one pair of opposite sides of a quadrilateral are both parallel and congruent, then it’s a parallelogram.
From the given quadrilateral ABCD:
AB=CD (Given)
∠1=∠2 (Given)
AC=AC (Diagonal)
From ASA congruency ΔABC and ΔADC are congruent.
By CPCT, AD=BC and ∠ABC=∠ADC.
Since opposite angles and sides are equal, then the quadrilateral ABCD is a parallelogram.
To learn more about parallelogram visit:
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Answer:
B and c.
Step-by-step explanation:
Area is: L x W.
8 x 3 = 24
6 x 4 = 24
Feel free to let me know if you need more help. :)
Answer:
80, 20 suvs in 45 vehicles, 45 is 1/4 of 180, so just multiply 20 times 4 and the answer you get is 80
Answer:
there is one real solution
Step-by-step explanation:
use the quadratic formula. what is in the square root is called the discriminant.
since it came out to 0 there is one real solution