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4 years ago

Hey I have a question. What is faithfulness in your opinion

Mathematics

2 answers:

DanielleElmas [232]4 years ago

4 0

Answer:

Faithful is a positive connotation meani g to be constantly true hearted and. loyal

Vsevolod [243]4 years ago

3 0

Answer:

The quality of being faithful

Step-by-step explanation:

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Find the slope of each line defined below and compare their values. Down-drop Less than, greater than, equal to.

Agata [3.3K]

Answer:

$\displaystyle equal\:to \\ Line\:B: 1 \\ Line\:A: -1$

Step-by-step explanation:

Starting from the y-intercept of $\displaystyle [0, -2],$ you do $\displaystyle \frac{rise}{run}$ by either moving one block south over one block west or one block north over one block east [west and south are negatives].

Now, for Line A, we need to convert this Linear Standard Equation to Slope-Intercept Form, $\displaystyle y = mx + b,$ where the slope is represented by m:

x + y = 3

- x - x

__________

$\displaystyle y = -x + 3$

So, the slope of Line A is $\displaystyle -1,$ and since −1 is less than 1, less than would be the answer, HOWEVER, they BOTH have some slope of 1, so since −1 is the negative absolute value of 1, equal to will be the answer.

I am joyous to assist you anytime.

4 0

3 years ago

Please help!! x = 2 - 3 cos t, y = 1 + 4 sin t in rectangular form? thank you! :)

sukhopar [10]

Answer:

$\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1$

Step-by-step explanation:

$x=2-3\cos(t)$

$y=1+4\sin(t)$

Let's solve for $\cos(t)$ in the first equation and then solve for $\sin(t)$ in the second equation.

I will then use the following identity to get right of the parameter, $t$ :

$\cos^2(t)+\sin^2(t)=1$ (Pythagorean Identity).

Let's begin with $x=2-3\cos(t)$ .

Subtract 2 on both sides:

$x-2=-3\cos(t)$

Divide both sides by -3:

$\frac{x-2}{-3}=\cos(t)$

Now time for the second equation, $y=1+4\sin(t)$ .

Subtract 1 on both sides:

$y-1=4\sin(t)$

Divide both sides by 4:

$\frac{y-1}{4}=\sin(t)$

Now let's plug it into our Pythagorean Identity:

$\cos^2(t)+\sin^2(t)=1$

$\frac{x-2}{-3})^2+(\frac{y-1}{4})^2=1$

$\frac{(x-2)^2}{(-3)^2}+\frac{(y-1)^2}{4^2}=1$

$\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1$

5 0

3 years ago

Read 2 more answers

I need help with number 3

Illusion [34]

A. Hope this helps!!!

5 0

3 years ago

Read 2 more answers

The diagram shows a 5 cm x 5 cm x 5 cm cube.

Nitella [24]

Answer:

8.7 cm

Step-by-step explanation:

The question is a 2-two-step Pythagoras theorem. (c^2 = a^2 + b^2)

Consider as such, If I were to draw a diagonal line along the base of the cube what is the length of the diagonal line. To find out that we use the theorem. We can substitute a for 5 and b for 5 as well. So

a^2 +b^2 = c^2

5^2 + 5^2 = c^2

25 + 25 = c^2

√50 = c

Then since the line side of the cube is on a 3d angle we need to do the same process again but now using the imaginary diagonal line that we just calculated and the height (5).

a^2 +b^2 = c^2

√50^2 + 5^2 = c^2

50 + 25 = c^2

√75 = c

c = 8.6602...

when rounded to 1 d.p.

c = 8.7

Line AB is 8.7 cm long.

7 0

4 years ago

Solve for x: 3x − 2 > 5x + 10. (5 points) 1) x > 6 2) x −6

san4es73 [151]