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lions [1.4K]
4 years ago
14

The equation x2 – 1x – 90 = 0 has solutions {a, b}. What is a + b?

Mathematics
2 answers:
lina2011 [118]4 years ago
8 0

Answer:

Value of a+b is:

1

Step-by-step explanation:

For a equation

Ax²+Bx+C=0

if {a,b} are its solutions or equation has roots a and b

Then, sum of roots= -B/A  and product of roots=C/A

i.e. a+b= -B/A  and ab=C/A

Here, the equation is:

x² – x – 90 = 0

i.e. A=1,B= -1 and C= -90

then, a+b= -(-1)/1

i.e. a+b=1

Hence, value of a+b is:

1

ololo11 [35]4 years ago
4 0
It can be factorised as
(x - 10)(x + 9)
so the solutions are
x= 10 and x = -9

so the sum of the solutions is 10 -9 which is 1
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LUCKY_DIMON [66]

Answer:

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Step-by-step explanation:

Given that:

-2 = 5 / (2x+3)

Multiplying both sides by (2x + 3)

-2(2x + 3) = 5

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3 years ago
A loss of $500 in stock market is worse than a gain of 200 in the stock market
Serhud [2]
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Can someone please help me with my maths
Korvikt [17]

Answer:

a

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Read 2 more answers
2. Find the general relation of the equation cos3A+cos5A=0
mars1129 [50]
<h2>Answer:</h2>

A=\frac{\pi}{8}+\frac{n\pi}{4}or\ A=\frac{\pi}{2}+n\pi

<h2>Step-by-step explanation:</h2>

<h3>Find angles</h3>

cos3A+cos5A=0

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<h3>Transform the expression using the sum-to-product formula</h3>

2cos(\frac{3A+5A}{2})cos(\frac{3A-5A}{2})=0

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<h3>Combine like terms</h3>

2cos(\frac{8A}{2})cos(\frac{3A-5A}{2})=0\\\\  2cos(\frac{8A}{2})cos(\frac{-2A}{2})=0

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<h3>Divide both sides of the equation by the coefficient of variable</h3>

cos(\frac{8A}{2})cos(\frac{-2A}{2})=0

________________________________________________________

<h3>Apply zero product property that at least one factor is zero</h3>

cos(\frac{8A}{2})=0\ or\ cos(\frac{-2A}{2})=0

________________________________________________________

<h2>Cos (8A/2) = 0:</h2>

<h3>Cross out the common factor</h3>

cos\ 4A=0

________________________________________________________

<h3>Solve the trigonometric equation to find a particular solution</h3>

4A=\frac{\pi}{2}or\ 4A=\frac{3\pi}{2}

________________________________________________________

<h3>Solve the trigonometric equation to find a general solution</h3>

4A=\frac{\pi}{2}+2n\pi \ or\\ \\ 4A=\frac{3 \pi}{2}+2n \pi\\ \\A=\frac{\pi}{8}+\frac{n \pi}{4\\}

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<h2>cos(-2A/2) = 0</h2>

<h3>Reduce the fraction</h3>

cos(-A)=0

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<h3>Simplify the expression using the symmetry of trigonometric function</h3>

cosA=0

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<h3>Solve the trigonometric equation to find a particular solution</h3>

A=\frac{\pi }{2}\ or\ A=\frac{3 \pi}{2}

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<h3>Solve the trigonometric equation to find a general solution</h3>

A=\frac{\pi}{2}+2n\pi\ or\ A=\frac{3\pi}{2}+2n\pi,n\in\ Z

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<h3>Find the union of solution sets</h3>

A=\frac{\pi}{2}+n\pi

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<h2>A = π/8 + nπ/4 or A = π/2 + nπ, n ∈ Z</h2>

<h3>Find the union of solution sets</h3>

A=\frac{\pi}{8}+\frac{n\pi}{4}\ or\ A=\frac{\pi}{2}+n\pi ,n\in Z

<em>I hope this helps you</em>

<em>:)</em>

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Step-by-step explanation:

<em>Refer to attached</em>

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Finding the required coordinate is shown on the graph

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