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3 years ago

What is 64cm2 converted

Mathematics

2 answers:

Bogdan [553]3 years ago

7 0

64cm2 converted into millimeters is 6400mm2

garri49 [273]3 years ago

3 0

the answer is 6400mm2

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A batter hits a baseball into the air. the height of the ball, in feet, is modeled by the quadratic function h(t), where t repre

velikii [3]

Answer:

C. h(9.8)=0

Step-by-step explanation:

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3 years ago

A piece for a board game is shaped like a triangular prism. The piece is 18 millimeters long. The base of the piece is an equila

Bogdan [553]

We can solve for the surface area of the triangular prism using the formula below:
SA=bh + (s1+s2+s3) H
where b for the base, h and H for the height while s1, s2 and s3 for the length of the sides of the equilateral triangles.
Solution is shown below:
SA=10*9+(10*10*10) *18
SA=90+(1000*18)
SA=1,620,000 u²

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3 years ago

X4 - 4k3 + 4k Factor out the GCF of all three terms<br>

Tatiana [17]

Answer:

Step-by-step explanation:

There isn't one. The first term is x^4.

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You can do 2 of the three. Terms 2 and 3 have a common factor of 4k, so what you can get is

x^4 - 4k(k^2 - 1)

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3 years ago

What is 0.33/0.75 as a decimal

mafiozo [28]

The answer is 0.44
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3 years ago

Read 2 more answers

A copyeditor thinks the standard deviation for the number of pages in a romance novel is six. A sample of 25 novels has a standa

alina1380 [7]

Answer:

No, the standard deviation for number of pages in a romance novel is six only.

Step-by-step explanation:

First we state our Null Hypothesis, $H_o$ : $\sigma$ = 6

and Alternate Hypothesis, $H_1$ : $\sigma$ > 6

We have taken these hypothesis because we have to check whether our population standard deviation is higher than what editor hypothesized of 6 pages in a romance novel.

Now given sample standard deviation, s = 9 and sample size, n = 25

To test this we use Test Statistics = $\frac{(n-1)s^{2} }{\sigma^{2} }$ follows chi-square with (n-1) degree of freedom [ $\chi ^{2}_n__-1$ ]

Test Statistics = $\frac{(25-1)9^{2} }{6^{2} }$ follows $\chi ^{2}_2_4$ = 54

and since the level of significance is not stated in question so we assume it to be 5%.

Now Using chi-square table we observe at 5% level of significance the $\chi ^{2}_2_4$ will give value of 36.42 which means if our test statistics will fall below 36.42 we will reject null hypothesis.

Since our Test statistics is more than the critical value i.e.(54>36.42) so we have sufficient evidence to accept null hypothesis and conclude that our population standard deviation is not more than 6 pages which the editor hypothesized.

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3 years ago