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3 years ago

How many significant figures will there be in the answer to the following

Mathematics

1 answer:

serious [3.7K]3 years ago

4 0

can you show me a picture then maybe i can help you

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What is the solution set for - 4x + 10 = 5x + 55?

Lina20 [59]

Answer:

x=−5

Step-by-step explanation:

Step 1: Subtract 5x from both sides.

−4x+10−5x=5x+55−5x

−9x+10=55

Step 2: Subtract 10 from both sides.

−9x+10−10=55−10

−9x=45

Step 3: Divide both sides by -9.

−9x

−9

x=−5

Answer:

x=−5

4 0

4 years ago

According to the manufacturer of a backup UPS device, the normal output voltage is 120 volts. The sample of 40 measured voltage

anyanavicka [17]

Answer:

z = 1.83<1.96

null hypothesis is accepted

The sample is came from a population mean

Step-by-step explanation:

Step :-1

The sample of 40 measured voltage amounts from a unit have a mean of 123.59 volts and a standard deviation of 0.31 volts

given sample size n =40

mean of the sample ×⁻ = 123.59 volts

standard deviation of sample σ = 0.31 volts

Step2:-

Null hypothesis :-

the sample is from a population with a mean equal to 120 volts.

H₀ : μ =120

Alternative hypothesis:-

H₁ : μ ≠120

level of significance:- α =0.05

Step 3:-

The test statistic

$z = \frac{x_{-}-mean }{\frac{S.D}{\sqrt{n} } }$

substitute values and simplification

$z = \frac{123.59-120}{\frac{0.31}{\sqrt{40} } }$

on simplification we get the calculated value

z = 1.83

The tabulated value z =1.96 at 0.05 % level of significance

Conclusion:-

Calculated Z < The tabulated value z =1.96 at 0.05 % level of significance

so the null hypothesis is accepted

The sample is came from a population mean

4 0

3 years ago

How do I simplify this question 2y+4-13-y

NemiM [27]

Answer:

Y=9

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A random sample of 401 student were recent survey regarding their class standing freshmen software junior senior and their major

SOVA2 [1]

the Solution

$Pr(\text{STEM)}=\frac{158}{401}=0.394$ $Pr(\text{Sophomore)}=\frac{87}{401}=0.217$ $Pr(sophomore|Non-stem)=\frac{68}{401}=0.170$ $Pr(\text{sophomore and Non-stem)=}\frac{87}{401}\times\frac{243}{401}=\frac{21141}{160801}=0.1315$

To ascertain whether Sophomore and Non-stem are dependent, we have to test the following:

$\begin{gathered} If\text{ Pr(sophomore or Non-stem) = Pr(sophomore and Non-stem),} \\ \text{then we conclude that both events are Independent,} \\ \text{otherwise, they are dependent.} \end{gathered}$ $\begin{gathered} Pr(\text{sophomore or Non-stem)=Pr(sophomore)+Pr(Non-stem)} \\ -Pr(\text{sophomore and Non-stem)} \end{gathered}$ $Pr(\text{Sophomore or Non-stem)=}\frac{87}{401}+\frac{243}{401}-(\frac{87}{401}\times\frac{234}{401})$ $=\frac{330}{401}-\frac{21141}{160801}=0.82294-0.13147=0.69147$

Cleary, we have that sophomore and non-stem events are dependent events since 0.69147 is not the same as 0.13147.

4 0

1 year ago

What is shape is this

OverLord2011 [107]

This is a rombus hope this helps!

7 0

3 years ago

Read 2 more answers