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kenny6666 [7]
3 years ago
11

What is the probability of 3c5​

Mathematics
1 answer:
frosja888 [35]3 years ago
3 0

Answer:

10

Step-by-step explanation:

The question is wrong it should be 5C3

5C3=5!/((5-3)!•3!)=5!/(2!•3!)

=(5•4•3•2•1)/(2•1•3•2•1)

=10

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Jeff buys a bag of cookies for $3.25. There is a tax on the cookies that is 2% of his total. How much does Jeff pay in total?
crimeas [40]

Answer:$3.19

Step-by-step explanation:

7 0
3 years ago
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What is the leading coefficient of 8 -5x+x^3-2x^4
Anon25 [30]

Answer:

-2

Step-by-step explanation:

8 -5x+x^3-2x^4

Write the polynomial from highest power of x to lowest power of x

-2x^4+x^3-5x+8

The leading coefficient is the number in front of the highest power of x

-2

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3 years ago
PLS HELP!!!!!!!!!!!!!<br>Write the recursive rule for the sequence: 5, -10, 20, -40, 80
earnstyle [38]

Answer:

<u>We observe that this is a GP  with:</u>

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<u>The nth term is:</u>

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6 0
3 years ago
Cars arrive at the Wendy's drive-through at a rate of 1 car every 5 minutes between the hours of 11:00 PM and 1:00 AM. on Saturd
mestny [16]

Answer:

1) P(X = 8) = 0.1033

P(X = 9) = 0.0688

2) Expected number of 200 restaurants in which exactly 8 customers use the drive-through: 20.66

Expected number of 200 restaurants in which exactly 9 customers use the drive-through: 13.76

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

Question 1. Use the Poisson distribution to calculate the probability that exactly 8 cars will use the drive-through between 12:00 midnight and 12:30 AM on a Saturday night at Wendy's. Do the same for exactly 9 cars.

Cars arrive at the Wendy's drive-through at a rate of 1 car every 5 minutes between the hours of 11:00 PM and 1:00 AM. on Saturday nights. This means that during 30 minutes, 6 cars expected to arrive. So \mu = 6.

P(X = 8)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 8) = \frac{e^{-6}*(6)^{8}}{(8)!} = 0.1033

P(X = 9)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 9) = \frac{e^{-6}*(6)^{9}}{(9)!} = 0.0688

Question 2. At how many of the 200 restaurants in the survey would you expect exactly 8 customers to use the drive-through? exactly 9 customers?

There is a 10.33 probability that 8 customers would use the drive through for each restaurant.

So of 200, the expected number is

E(X) = 200*0.1033 = 20.66

There is a 6.88 probability that 9 customers would use the drive through for each restaurant.

So of 200, the expected number is

E(X) = 200*0.0688 = 13.76

8 0
3 years ago
What is the order of rotational symmetry for the figure?
mylen [45]

C is the right answer.

Trust me char!!

Na bakla na yswa!

7 0
2 years ago
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