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3 years ago

20 points! Mean, Median, and mode (image below).

Mathematics

1 answer:

antoniya [11.8K]3 years ago

5 0

Mean = 75.8
median = 76.5
mode = 63

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Eric returned from a trip with 300 which is 50% more money than he had at the beginning of his trip how much money did Eric have

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he had 150.

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What would 0.5598 × 908÷66 be

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4 years ago

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The perimeter of a rectangular field is 48m, if the length is twice the width . Find the area of the field.

kari74 [83]

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128 m^2

Step-by-step explanation:

Perimeter = 48

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Darya [45]

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x ≥ 5

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$30 - (1 * $20)

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3 years ago

Help please!!!!!!!!!

dmitriy555 [2]

Answer:

$f\left(0\right)=\left(0\right)^2-4\left(0\right)=0-0=0$

$f\left(1\right)=\left(1\right)^2-4\left(1\right)=1-4=-3$

$f\left(2\right)=\left(2\right)^2-4\left(2\right)=4-8=-4$

$f\left(3\right)=\left(3\right)^2-4\left(3\right)=9-12=-3$

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Step-by-step explanation:

Given the function

$f\left(x\right)=x^2-4x$

Putting x=0 in the equation to find f(0)

$f\left(x\right)=x^2-4x$

$f\left(0\right)=\left(0\right)^2-4\left(0\right)=0-0=0$

Putting x=1 in the equation to find f(1)

$f\left(x\right)=x^2-4x$

$f\left(1\right)=\left(1\right)^2-4\left(1\right)=1-4=-3$

Putting x=2 in the equation to find f(2)

$f\left(x\right)=x^2-4x$

$f\left(2\right)=\left(2\right)^2-4\left(2\right)=4-8=-4$

Putting x=3 in the equation to find f(3)

$f\left(x\right)=x^2-4x$

$f\left(3\right)=\left(3\right)^2-4\left(3\right)=9-12=-3$

Putting x=4 in the equation to find f(4)

$f\left(x\right)=x^2-4x$

$f\left(4\right)=\left(4\right)^2-4\left(4\right)=16-16=0$

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3 years ago