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Kruka [31]
3 years ago
7

Simplify:2 1/3(4 1/4÷2)

Mathematics
1 answer:
kondor19780726 [428]3 years ago
4 0

Answer:

4\frac{23}{24}

Step-by-step explanation:

We want to simplify:

2\frac{1}{3}(4\frac{1}{4}\div 2)

We convert to improper fraction to get:

\frac{7}{3}(\frac{17}{4}\div 2)

We now deal with the parenthesis by multiplying with the reciprocal of 2.

\frac{7}{3}(\frac{17}{4}\times \frac{1}{2} )

This gives:

\frac{7}{3}(\frac{17}{8})

We multiply to get:

\frac{7}{3}(\frac{17}{8})

This simplfies to:

\frac{119}{24}

We write as mixed number

4\frac{23}{24}

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PLZ HELP ITS 20 POINTS AND THIS IS THE LAST QUESTION TO MY TEST
Marizza181 [45]

Answer:

C

Step-by-step explanation:

8 0
3 years ago
A certain plant runs three shifts per day. Of all the items produced by the plant, 50% of them are produced on the first shift,
Snezhnost [94]

Answer:

0.2941 = 29.41% probability that it was manufactured during the first shift.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Defective

Event B: Manufactured during the first shift.

Probability of a defective item:

1% of 50%(first shift)

2% of 30%(second shift)

3% of 20%(third shift).

So

P(A) = 0.01*0.5 + 0.02*0.3 + 0.03*0.2 = 0.017

Probability of a defective item being produced on the first shift:

1% of 50%. So

P(A \cap B) = 0.01*0.5 = 0.005

What is the probability that it was manufactured during the first shift?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.005}{0.017} = 0.2941

0.2941 = 29.41% probability that it was manufactured during the first shift.

6 0
2 years ago
Given the formula a = s2 + 3b - c , find the value of a when s = 7, b = 13 and c = -24.
galben [10]

Answer:

a = 112

Step-by-step explanation:

a =s^{2} +3b-c

Given that,

s = 7

b = 13

c = (-24)

Let's solve for a now.

a =s^{2} +3b-c

a = 7^{2} +3*13-(-24)\\

a=49+39+24\\

a=88+24

a=112

Hope this helps you.

Let me know if you have any other questions :-)

3 0
3 years ago
ILL BRAINLIEST YOU PLEASE HELP ME
joja [24]

Answer:

82°

Step-by-step explanation:

6 0
2 years ago
Find two consecutive even integers such that twice the smaller is 16 more than the larger
drek231 [11]
<u>Define x:</u>
Let one of the numbers be x.
The other number is x + 2

<u>Construct equation:</u>
<span>twice the smaller is 16 more than the larger
</span>⇒2x = x + 2 - 16

<u>Solve x:</u>
2x = x + 2 - 16
x = -14

<u>Find the two numbers:</u>
Smaller number = x = -14
Larger number = x + 2 = -12

Answer: The two numbers are -14 and -12
6 0
2 years ago
Read 2 more answers
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