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maria [59]
3 years ago
6

Please help I have no clue what to do

Mathematics
1 answer:
Maurinko [17]3 years ago
6 0
Because its not quite clear if the 5 is negative you might want to try once with a positive and once with it negative. anyway, when you only have multiplication like this, so no addition or subtraction, you can "distribute"the exponent on the outside of the parenthesis. so the first two terms become 8^(-2/3)(w^7)^(-2/3) hopefully you can figure out the rest. from here, with w if you have something to an exponent which is also to an exponent, you can multiply the exponents. so that's 7*(-2/3) which is-14/3. let me know if you have trouble with fraction multiplication. now negative exponents have something special about them. if you have a negative exponent you can write it as one over that term with a positive exponent. so the first term becomes 1/(8^(2/3)) which is 1/4.
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Compute the amount of interest earned in the following simple interest problem.
Mumz [18]

Answer:

Step-by-step explanation:

P = $295

r =7%

t = 270 days = 270/365

Interest = Prt

=295*\frac{7}{100}*\frac{270}{365}\\\\= 15.28

= $ 15.28

Amount  = 295 + 15.28

Amount = $310.28

4 0
3 years ago
What is the equation of the circle with center (−3, 1) that passes through the point (−5, 3)?
Mariulka [41]

Answer:

( x + 3)^2 + ( y - 1)^2 = 8

Step-by-step explanation:

The equation of a circle with a center and a point

( x - a) ^2 + ( y - b) ^2 = r^2

( x , y) - any point on the circle

( a, b) - center of the circle

r^2 - radius of the circle

( -3 , 1) - center - ( a, b)

a = -3

b = 1

( -5 , 3) - point - ( x, y)

x = -5

y = 3

Step 1: substitute the center into the equation

( x -(-3)^2 + ( y - 1)^2 = r^2

( x + 3)^2 + ( y - 1)^2 = r^2

Step 2 : sub the point into the equation

( x + 3)^2 + ( y - 1)^2 = r^2

( -5 + 3)^2 + ( 3 - 1)^2 = r^2

(-2)^2 + 2^2 = r^2

4 + 4 = r^2

8 = r^2

Step 3 : sub the radius into the equation

( x + 3)^2 + ( y - 1)^2 = r^2

( x + 3)^2 + (y - 1)^2 = 8

Therefore, the equation of the circle is

( x + 3)^2 + (y - 1)^2 = 8

6 0
3 years ago
What is the slope of a perpendicular line 2x + y = 6<br><br> is answer -2
Firdavs [7]

Answer:

The slope that is perpendicular to the line will be:

m_2=+\frac{1}{2}

Step-by-step explanation:

Given the equation

2x\:+\:y\:=\:6\:

We know that

y=mx+b is the slope-intercept form of a line where m is the slope and b is the y-intercept.

So, writing the equation in the slope-intercept form

2x\:+\:y\:=\:6\:

\:y=-2x+6

here

m=-2        ∵  y=mx+b        

As we know that for perpendicular lines, one slope is the negative reciprocal of the other.

Therefore, the slope that is perpendicular to the line will be:

m_2=+\frac{1}{2}

3 0
3 years ago
Solve to x to the nearest foot
Arisa [49]

Answer:

x= 1325 ft (nearest foot)

Step-by-step explanation:

Please see the attached pictures for the full solution.

3 0
2 years ago
Help plz with Algebra question I attached a file
astraxan [27]

Answer:

x=4.63

Step-by-step explanation:

Area = (1/2) (base) (height)

20 = (1/2) (x+4) (x)

40 = x²+4x

x²+4x-40=0

Put in quadratic equation:

x=\frac{-4(+/-)\sqrt{4^{2}-4(1)(-40) } }{2(1)}

x=\frac{-4(+/-)\sqrt{176} }{2}

x=4.63324958071 or x=-8.63324958071

Since x can't be negative in this case we take our answer to be 4.63324958071, which rounds to 4.63

5 0
2 years ago
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