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Ahat [919]
3 years ago
7

Simplify the radical expression by rationalizing the denominator 4/√21

Mathematics
2 answers:
Tcecarenko [31]3 years ago
4 0

\frac{4}{\sqrt{21}} =\frac{4\sqrt{21}}{\sqrt{21}\sqrt{21}} =\frac{4\sqrt{21}}{21}

Lynna [10]3 years ago
3 0

I think

\dfrac{4}{\sqrt{21}}

is about as simple as this is going to get. For some reason teachers like the radicals in the numerator, so we multiply top and bottom by \sqrt{21} and get

\dfrac{4}{\sqrt{21}} \times \dfrac{\sqrt{21}}{\sqrt{21}} = \dfrac{4\sqrt{21}}{21}

Answer: \dfrac{4\sqrt{21}}{21}

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Stacey has a square piece of cloth. She cuts 3 inches off of the length of the square and 3 inches
Mamont248 [21]

Answer:

6 in

Step-by-step explanation:

Let x = the side length of the original square.

They removed 3 in from each side of the original square, so the side lengths of the remaining square are x - 3 in.

The area of the smaller square is (x - 3)².

The area of the original square is x²

I assume the area of the smaller square is ¼ that of the original square. Then

1. Solve for x

\begin{array}{rcl}\frac{1}{4}x^{2} & = & (x - 3)^{2}\\x^{2} & = & 4(x - 3)^{2}\\& = & 4(x^{2} - 6x + 9)\\x^{2}& = & 4x^{2} - 24x + 36\\3x^{2} - 24x + 36 & = & 0\\x^{2} - 8x + 12 & = & 0\\(x - 2)(x - 6) & = & 0\\x - 2 = 0& \qquad &x - 6 = 0\\x = 2& \qquad &x = 6\\\end{array}

2. Calculate the side length of the smaller square

(a) x = 2

Side length = x - 3 = 2 - 3 = -1 in.

IMPOSSIBLE. You can't have a negative side length.

(b) x = 6

Side length of smaller square = 6 - 3 = 3 in.

Side length of original square = x = 6 in

Check:

\begin{array}{rcl}\frac{1}{4}(6)^{2} & = & (6 - 3)^{2}\\\frac{1}{4}\times 36 & = & 3^{2}\\9 & = & 9\\\end{array}

OK.

3 0
3 years ago
Use the diagram to answer, given that line LM is a common tangent to circle P and circle Q. Leave answers in simplified radical
drek231 [11]

Answer:

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PN = 5√5

Step-by-step explanation:

8/12 = 6/PL

8PL = 72

PL = 9

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sattari [20]

Answer:

Dilation

Step-by-step explanation:

Given

Main function: f(x)

Resulting function: 5f(x)

Required

Which transformation exists between both functions

The general explanation is that:

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Mathematically, if the following relationship exists between f(x) and g(x)

g(x) = k.f(x)

Then g(x) is a dilation of f(x) and k is the constant of proportionality or dilation ratio

In this case:

g(x) = 5f(x)

So, the transformation that answers the question is dilation.

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