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3 years ago

What is the measure of the missing angle? 90° 600 7.

Mathematics

1 answer:

RideAnS [48]3 years ago

4 0

Answer:

30°

Step-by-step explanation:

Let the measure of the missing angle be x°

Therefore, by interior angle sum postulate of a triangle:

x + 60° + 90° = 180°

x + 150° = 180°

x = 180° - 150°

x = 30°

Thus the measure of the missing angle is 30°.

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The degree measure of an angle in a right triangle is x, and sin x = 0.354, which of the following expressions is also equal to

almond37 [142]

What are the expressions?

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3 years ago

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Which equation represents a line which is parallel to the line 3x - y = 6?

DochEvi [55]

Step-by-step explanation:

We just have to remember the line equation <u>y=mx+b</u> , then place the given equation into this form (y= -3x-6).

Remember that (m) is your slope. So, to find a parallel line, they must have an equal slope. Check the other equations and see which one had a slope of -3. The answer C also has a slope of -3. So those lines would be parallel.

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3 years ago

Q and D are vertices of a polygon. Q' and D' are vertices of the polygon's image after a translation. Determine the translation,

snow_lady [41]

Answer:

(6,—6)

Step-by-step explanation:

Draw the points on a table. The answer will be (6,—6)

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2 years ago

A quadratic equation is shown below:

sweet [91]

Answer:

Part A:

( 1.8333, -0.08333)

Part B:

x = 2 or x = 5/3

Step-by-step explanation:

The quadratic equation

$3x^{2}-11x+10=0$ has been given.

Part A:

We are required to determine the vertex. The vertex is simply the turning point of the quadratic function. We shall differentiate the given quadratic function and set the result to 0 in order to obtain the co-ordinates of its vertex.

$\frac{d}{dx}(3x^{2}-11x+10)=6x-11$

Setting the derivative to 0;

6x - 11 = 0

6x = 11

x = 11/6

The corresponding y value is determined by substituting x = 11/6 into the original equation;

y = 3(11/6)^2 - 11(11/6) + 10

y = -0.08333

The vertex is thus located at the point;

( 1.8333, -0.08333)

Find the attached

Part B:

We can use the quadratic formula to solve for x as follows;

The quadratic formula is given as,

$x=\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}$

From the quadratic equation given;

a = 3, b = -11, c = 10

We substitute these values into the above formula and simplify to determine the value of x;

$x=\frac{11+/-\sqrt{11^{2}-4(3)(10) } }{2(3)}=\frac{11+/-\sqrt{1} }{6}\\\\x=\frac{11+/-1}{6}\\\\x=\frac{11+1}{6}=2\\\\x=\frac{11-1}{6}=\frac{5}{3}$

6 0

3 years ago

Anyone know the answer to this

Vesna [10]

Answer:

Part A:

- angle ACB= 60° (ABC equilateral triangle.)

- Angle ECD=EDC= (180°-32°)/2= 148/2= 74° (sum of angles in a triangle is equal to 180, and triangle ECD is isosceles since it's given that CE=DE.

- x= 180°-(60°+74°)

= 180°-134°

= 46°

x= 46°

Part B:

120°

3 0

2 years ago