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andrew-mc [135]
3 years ago
7

(+1)+(+4) =

Mathematics
2 answers:
marishachu [46]3 years ago
6 0

Answer:

5

8

3

15

8

16

6

6

10

3

3

9

14

6

9

9

Step-by-step explanation:

Sergeeva-Olga [200]3 years ago
3 0

Answer:

+ 1 + 4 = 5 \\  + 7 + 1 = 8 \\  + 2 + 1 = 3 \\  + 7 + 8 = 15 \\  + 2 + 6 = 8 \\  + 9 + 7 = 16 \\  + 5 + 1 = 6 \\  + 3 + 3 = 6 \\  + 4 + 6 = 10 \\  + 2 + 1 = 3 \\  + 2 + 1 = 3 \\  + 2 + 7 = 9 \\  + 8 + 6 = 14 \\  + 2 + 4 = 6 \\  + 6 + 3 = 9 \\  + 4 + 5 = 9

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The pentagon is the one with 5 sides. Good Luck!

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$147.68 is the awnser too this one
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Solve the inequality. 2n/7 ≤ 4, but it needs to be in set-notation.
son4ous [18]

Answer

n <u>< </u>14

Step-by-step explanation:

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6 0
3 years ago
Match each equation with its solution set. Tiles a2 − 9a + 14 = 0 a2 + 9a + 14 = 0 a2 + 3a − 10 = 0 a2 + 5a − 14 = 0 a2 − 5a − 1
sattari [20]
We have that

N 1)
a²<span> − 9a + 14 = 0 
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 9a)=-14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² − 9a+20.25)=-14+20.25

Rewrite as perfect squares

(a-4.5)²=6.25--------> (a-4.5)=(+/-)√6.25

a1=4.5+√6.25-----> a1=7

a2=4.5-√6.25-----> a2=2

the solution problem N 1 is the pair {7, 2}


N 2) 

a²<span> + 9a + 14 = 0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 9a)=-14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² +9a+20.25)=-14+20.25

Rewrite as perfect squares

(a+4.5)²=6.25--------> (a+4.5)=(+/-)√6.25

a1=-4.5+√6.25-----> a1=-2

a2=-4.5-√6.25-----> a2=-7

the solution problem N 2 is the pair {-2,-7}

N 3) 

a² + 3a − 10 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 3a)=10

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² + 3a+2.25)=10+2.25

Rewrite as perfect squares

(a+1.5)²=12.25------> (a+1.5)=(+/-)√12.25

a1=-1.5+√12.25-----> a1=2

a2=-1.5-√12.25-----> a2=-5

the solution problem N 3 is the pair {2, -5}


N 4)

a²<span> + 5a − 14 = 0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 5a) =14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² + 5a+6.25) =14+6.25

Rewrite as perfect squares

(a+2.5)² =20.25-------> (a+2.5)=(+/-)√20.25

a1=-2.5+√20.25-----> a1=2

a2=-2.5-√20.25-----> a2=-7

the solution problem N 4 is the pair {2, -7}


N 5) 

a² − 5a − 14 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 5a)=14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² − 5a+6.25)=14+6.25

Rewrite as perfect squares

(a-2.5)²=2025--------> (a-2.5)=(+/-)√20.25

a1=2.5+√20.25-----> a1=7

a2=2.5-√20.25-----> a2=-2

the solution problem N 5 is the pair {7, -2}

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3 years ago
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Can please answer these 3 questions
kupik [55]
So it would be 32 lol if
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