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julia-pushkina [17]
3 years ago
7

Each container holds 1L 275ml of water. How much water is in 609 identical containers? Find the difference between your estimate

d product and precise product.
Mathematics
1 answer:
yan [13]3 years ago
7 0
Do the conversion of 1l to ml and add 275 plus that number then multiply
You might be interested in
F(x) = (x - 2)²(x+1)​
Inessa [10]

(x - 2)²(x+1)​

(x-2)(x-2)

multiply the two brackets together

(x)(x)=x^2

(x)(-2)=-2x

(-2)(x)=-2x

(-2)(-2)=4

x^2-2x-2x+4

x^2-4x+4

(x^2-4x+4)(x+1)

multiply the brackets together

(x^2)(x)=x^3

(x^2)(1)=x^2

(-4x)(x)=-4x^2

(-4x)(1)=-4x

(4)(1)=4

x^3+x^2-4x^2-4x+4x+4

Answer:

x^3-3x^2+4

5 0
3 years ago
Select the correct answer.
makvit [3.9K]

Answer:

<h3>64°</h3>

Step-by-step explanation:

y = 52° ( Opposite Angles )

y + 2x = 180° ( Interior Angles )

y + 2x =  {180}^{o}  \\  {52}^{o}  + 2x =  {180}^{o}  \\ 2x =  {180}^{o}  -  {52}^{o}  \\ 2x =  {128}^{o}  \\ x =  \frac{ {128}^{o} }{2} \\ x =  {64}^{o}  \\

3 0
2 years ago
What is the change in temperature from -8°F to 14°F?
gizmo_the_mogwai [7]

Answer:

22 degrees, 1. 2 degrees, 2. 14 degrees, 3. 14 degrees, 4.30 degrees

Step-by-step explanation:

6 0
3 years ago
Perry is buying an I phone that is a sale for 40% off the original price.after he uses a $25 gift card.the total cost before tax
marta [7]

Answer:

$599

Step-by-step explanation:

Given: Discount- 40% off on original price.

           Gift card= $25

           Total cost before taxes is $334.40

Lets assume the original price be "x".

We know there is 40% on original price and Perry uses $25 gift card.

Remember; Total cost= Original\ price- discount- gift\ card

Now, finding the original price of Iphone.

⇒ x-0.40x-25= 334.40

⇒ 0.60x-25= 334.40

Adding both side by 25

⇒0.60x= 334.40+25

⇒0.60x= 359.4

Dividing both side by 0.60

⇒ x= \frac{359.4}{0.60}

∴ x= 599

Hence, the original price of iphone is $599

5 0
3 years ago
Without calculating, which has a bigger volume. A cube that has a length, width, and height of 18 m. Or a sphere with a radius o
Evgesh-ka [11]

Weird. A period appears above this... huh.

Answer:

[Th]e cube has a greater value.

Step-by-step explanation:

What the word problem really wants us to get [is ]the question of 'Which is greater, A=6a^2 when 'a' [is] 18 or A=4\pir^2 when r = 9? And here's how to solve that.

Starting with the[ c]ube we have A=6a^2. A bit t[o]o simple, right?

A=6(18)^2 Substitute numbers.

A=6(324) Solve ex[p]onents.

A=1944 Mult[i]ply.

So w[e] know that the cube is 1944 meters cube[d ] in area. But what about the more [f]ormidable sphere? Fo[r] it we need a slightly m[o]re co[m]plicated formula, A=4\pir^2. However, instead of using the real pi I will be rounding to 3.14, since we have no calculator so anything more would take way too long and fry your[ bra]in.

A=4(3.14)(9)^2 Subst[i]tute numbers.

A=4(3.14)(81) Solve expone[n]ts.

A=12.56(81) Multip[ly].

A=1017.36 Multiply again[.]

Now, since I'm sure all of us can count, we know that 1944 is greater than 1017.36. Or in other words, the cube is bigger than the sphere.

And PLEASE don't copy this guys. Make your own iteration. Change it up!

3 0
3 years ago
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