50mph
Step-by-step explanation:
The image of the motion of Paul's derive is attached already.
From the line graph we can obtain a lot of information that will help us unravel the average speed of Paul within the given time frame.
What is average speed?
Average speed is the rate of change of total distance covered with time taken .
Average speed = 
To find the total distance covered;
Distance at time 1 = 75miles
Distance at time 4 = 225miles
Distance covered between 1 - 4 = 225 - 75 = 150miles
Time taken for the journey = 4 - 1 = 3hrs
Input the values in the equation;
Average speed =
= 50mph
learn more:
Speed and motion brainly.com/question/10048445
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Area of pool edge = Area of big rectangle - Area of the pool
Area of pool edge = Area of the pool = 40 × 60 = 2400 ft²
2400 = Area of big rectangle - 2400
Area of big rectangle = 2400 + 2400
Area of big rectangle = 4800
Length × width = 4800
From the diagram, we need the length to be [x + x] more than the length of the pool, where x is the distance from the pool edge to the patio edge.
We also need the width of the big rectangle to be [[x + x] more than the width of the pool.
Length = 60 + 2x
Width = 40 + 2x
Length × Width = [60+2x] × [40+2x]
4800 = 2400 + 120x + 80x + 4x²
0 = 4x² + 200x - 2400
0 = 4[x² + 50x - 600]
0 = x² + 50x - 600
0 = [x - 60] [x + 10]
x - 60 = 0 OR x + 10 = 0
x = 60 OR x = -10
We can only use the positive value of x since the context is length
Hence, x = 60
Answer:
y = 5
Step-by-step explanation:
Since this is an isosceles triangle, Angle B and Angle C are equivalent. We can use this to find x
3x = 75
x = 25
Angles in a triangle add up to 180, so knowing the measure of Angle B and Angle C, we can find the measure of Angle A
Angle A = 180-(75+75)
Angle A = 180-150
Angle A = 30
We know Angle A = 4y+10
4y + 10 = 30
4y = 20
y = 5
I think 4/5 because if you multiply you get that!!!!!!
Team B has a mode of 60, which is the highest mode of all three teams. Team A has a mode of 48 and Team C has a mode of 30. Mode is the number that occurs most frequently in the set of data.