For this case we have by definition, that the total surface area of a regular pyramid with a square base is given by:

Where:
p: It is the perimeter of the base
S: It's the inclination
It is the area of the base
Substituting:

ANswer:
Option B
(2-5i)(3+i)
use foil method to expand it into standard form
6+2i-15i+5i^2
5i^2-13i+6
Yeah I think x=12y on this one correct me if I’m wrong
It should have 2 solutions
Answer:
16682.7 cm³
Step-by-step explanation:
The total volume is the volume of the cone plus half the volume of a sphere:
V = ⅓ π r² h + ½ (4/3 π r³)
V = ⅓ π r² h + ⅔ π r³
V = ⅓ π r² (h + 2r)
Given that r = 4.15 cm and h = 10.2 cm:
V = ⅓ π (4.15)² (10.2 + 2×4.15)
V ≈ 333.65
The volume needed for 50 cones is therefore:
50V ≈ 16682.7 cm³