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Vikki [24]
3 years ago
8

A is the point (-2, 0) and B is the point (0, 4).Find the equation of the straight line joining A and B.

Mathematics
1 answer:
Rus_ich [418]3 years ago
6 0

Answer:

y = 2*x + 4

Step-by-step explanation:

We know that a linear function can be written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

We know that if this line passes through the points (x₁, y₁) and (x₂, y₂) the slope can be written as:

a = (y₂ - y₁)/(x₂ - x₁)

So, here we know that our line must pass through the points (-2,0) and (0, 4)

Then the slope of this line is:

a = (4 - 0)/(0 - (-2))

a = 4/2 = 2

Then our line is something like:

y = 2*x + b

Now, to find the value of b we can use one of these two points, for example if we use the point (-2, 0), we know that, when x = -2, we must have y = 0.

0 = 2*(-2) + b

0 = -4 + b

4 = b

Then the equation for our line is:

y = 2*x + 4

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For what values of q are the two vectors A = i + j + kq each other and B-iq-23 + 2kg perpendicular to
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Answer:

The value of q are 0.781,-1.281.

Step-by-step explanation:

Given : Two vectors A=i+j+kq and B=iq-2j+2kq are perpendicular to each other.

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Solution :

When two vectors are perpendicular to each other then their dot product is zero.

i.e. \vec{A}\cdot \vec{B}=0

Two vectors A=i+j+kq and B=iq-2j+2kq

(i+j+kq)\cdot (iq-2j+2kq)=0

(1)(q)+(1)(-2)+(q)(2q)=0

q-2+2q^2=0

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2q^2+q-2=0

Using quadratic formula,

q=\frac{-1\pm\sqrt{1^2-4(2)(-2)}}{2(2)}

q=\frac{-1\pm\sqrt{17}}{4}

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q=0.781,-1.281

Therefore, The value of q are 0.781,-1.281.

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Step-by-step explanation:

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Step-by-step explanation:

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