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Alex Ar [27]
3 years ago
9

What is the opposite of –|–1|

Mathematics
2 answers:
Studentka2010 [4]3 years ago
8 0
It is I hope tha I help you
Marianna [84]3 years ago
6 0
What is the opposite of -|-1| so what is the opposite of -1? It's 1!!! Hope this helped!
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Write the following repeated multiplication using exponents. 6*6*6*6*6 (**Please use the ^ sign to show powers; for example, 5*5
kondaur [170]

Answer:

6^5

Step-by-step explanation:

6×6×6×6×6=7776

So 6^{5}=7776

5 0
3 years ago
A 40-pound bag of dog food costs $38. How much does the dog food cost per pound?
Amiraneli [1.4K]
$0.95 I think... all u need to do is divide the $38 by 40 and you’ll get $0.95 as the answer
4 0
3 years ago
Read 2 more answers
Joe deposits $3000 into an account that pays simple interest at an annual rate of 6%. He does not make any more deposits. He mak
Vlad [161]

Answer:

The interest is $1080 and the amount is $4080.

Step-by-step explanation:

Find an interest by using the formula I=P*i*t, where I is interest, P is total principal, i is rate of interest per year, and t is total time in years.

In this examplee P = $3000, i = 6% and t = 6 years, so

I=P*i*t

I=3000*0.06*6

I=1080

The interest is 1080, therefore the total amount is 4080.

Hope this helps!

8 0
2 years ago
WILL MARK BRANILST IF RIGHT PLEASE HELP FAST
kifflom [539]

(– 1)(2)(– 3)(– 4)

= -2(-3)(-4)

= 6(-4)

=-24

Answer: -24

6 0
3 years ago
Read 2 more answers
Exposure to ionizing radiation is known to increase the incidence of cancer. One thousand laboratory rats are exposed to identic
mojhsa [17]

Missing information :

The model was omitted from the question ; the possible model relating to the question was browsed online and could possibly be :

N(t) = 1.07t^2.3 for 0 ≤ t ≤ 10 months

Answer:

30.9 cases per month

Step-by-step explanation:

Given the model to determine the number of rats that have developed cancer after initial exposure ; N(t) = 1.07t^2.3

N(t) = 1.07t^2.3

Take the first derivative of N with respect to t to obtain the rate of change ;

N'(t) = (1.07)(2.3)t^2.3-1

N'(t) = (1.07)(2.3)t^1.3

The rate of growth of cancer cases at the 7th month can be calculated thus :

t = 7

N'(7) = (1.07)(2.3)t^1.3

N'(7) = 1.07 * 2.3 * 7^1.3

N'(7) = 1.07 * 2.3 * 12.549529

N'(7) = 30.884

The rate of growth of cancer at the 7th month is 30.9 cases per month.

7 0
3 years ago
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