$\bf ~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{3}x^2\stackrel{\stackrel{b}{\downarrow }}{-1}x\stackrel{\stackrel{c}{\downarrow }}{+6} \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ x=\cfrac{ - (-1) \pm \sqrt { (-1)^2 -4(3)(6)}}{2(3)}\implies x=\cfrac{1\pm\sqrt{1-72}}{6} \\\\\\ x=\cfrac{1\pm\sqrt{-71}}{6}\implies x=\cfrac{1\pm i\sqrt{71}}{6}\implies x= \begin{cases} \cfrac{1+ i\sqrt{71}}{6}\\[1em] \cfrac{1- i\sqrt{71}}{6} \end{cases}$

3 0

4 years ago

Four bunches of seedless black grapes costs $8. How many bunches can you buy for $20

Keith_Richards [23]

Answer:

Hi there

Your answer is

10 Bunches

Step-by-step explanation:

4 bunches= 8$

/8 for how many bunches per 1$

.5bunches= 1$

*20

10bunches=20$

8 0

3 years ago

Read 2 more answers

Please help me with this math problem

Lera25 [3.4K]

Answer:

Step-by-step explanation:

2x + 6 Solve for x

First get x by itself

2 / 2 cancels out. 6 / 2 = 3.

x + 2 3= x so that is 3 + 2 and it equals 5.

22 - 17 =5

7 0

3 years ago

If the math Olympiad club consists of 14 students, how many different teams of 5 students can be formed for competitions?

aliina [53]

Answer:

Step-by-step explanation:

5 x 2 = 10

5 x 3 = 15 > 14

therefore...

there are 2 teams of 5

6 0

4 years ago