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4 years ago

Katarina made a frequency distribution, setting up groups for the data shown.

Mathematics

1 answer:

Tresset [83]4 years ago

5 0

147 63 82 101 155 160 175 92 116 138 74 93 110 162 154 105 97

The frequency to her third group is 80 - 99.

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Find the other end point<br> Endpoint (5,-1) Midpoint (5,10)

dusya [7]

Answer:

(5, 21)

Step-by-step explanation:

The x-coordinate of the midpoint of a segment is half of the sum of the x-coordinates of the endpoints.

The y-coordinate of the midpoint of a segment is half of the sum of the y-coordinates of the endpoints.

Let the unknown point have coordinates (x, y).

x-coordinate:

(5 + x)/2 = 5

5 + x = 10

x = 5

y-coordinate:

(-1 + y)/2 = 10

-1 + y = 20

y = 21

The other endpoint has coordinates (5, 21).

8 0

4 years ago

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There is a picture attached *try to show work*

Harlamova29_29 [7]

Replace F in the equation with 113.

5/9(113-32)

5/9(81)

5 * 81 = 405
405 / 9 = 45 degrees Celcius

5 0

3 years ago

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Your credit limit is $2,500 what is the max you should ever owe on this card?

lions [1.4K]

Answer: $2,000

To calculate the max amount you should owe, multiply the credit limit by 80%. $2,500 * 80% = 2,000

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4 years ago

Write an equation of the line containing the point (6,-4) and perpendicular to.the line y=-2x-3

igor_vitrenko [27]

Answer:

$y=\frac{1}{2}x-7$

Step-by-step explanation:

So we need to find an equation of a line that crosses the point (6,-4) and is perpendicular to y = -2x -3.

First, let's find the slope of the line we want to write. The line we want is perpendicular to y = -2x -3. Recall that if two lines are perpendicular to each other, their slopes are negative reciprocals of each other. What this means is that:

$m_1\cdot m_2=-1$

Plug -2 for one of the slopes.

$-2\cdot m_2=-1$

Divide by -2 to find the slope of our line.

$m_2=1/2$

Thus, our line needs to have a slope of 1/2.

Now, let's use the point-slope form. The point-slope form is given by:

$y-y_1=m(x-x_1)\\$

Plug in 1/2 for the slope m and let's let our point (6,-4) be x₁ and y₁. Thus:

$y-(-4)=\frac{1}{2}(x-6)\\$

Simplify and distribute:

$y+4=\frac{1}{2} x-3$

Subtract 4 from both sides:

$y=\frac{1}{2}x-7$

The above is the equation that passes the point (6,-4) and is perpendicular to y = -2x -3.

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3 years ago

Ashley took $20 out of her savings account each week on Friday how many weeks ago did she have at least $250 in her account

Aloiza [94]

She had 250 in about 13 weeks

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3 years ago

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