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3 years ago

Which of these questions are equivalent to 1/4

Mathematics

2 answers:

tensa zangetsu [6.8K]3 years ago

7 0

B) 2/8 that’s the answer :p

alex41 [277]3 years ago

7 0

It would be B 2/8 !!!!!

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I WILL MARK YOU BRAINLYEST if you answer all of my problems !!!!!!!!!!!

Romashka [77]

First, let's convert each line to slope-intercept form to better see the slopes.

Isolate the y variable for each equation.

2x + 6y = -12

Subtract 2x from both sides.

6y = -12 - 2x

Divide both sides by 6.

y = -2 - 1/3x

Rearrange.

y = -1/3x - 2

Line b:

2y = 3x - 10

Divide both sides by 2.

y = 1.5x - 5

Line c:

3x - 2y = -4

Add 2y to both sides.

3x = -4 + 2y

Add 4 to both sides.

2y = 3x + 4

Divide both sides by 2.

y = 1.5x + 2

Now, let's compare our new equations:

Line a: y = -1/3x - 2

Line b: y = 1.5x - 5

Line c: y = 1.5x + 2

Now, the rule for parallel and perpendicular lines is as follows:

For two lines to be parallel, they must have equal slopes.

For two lines to be perpendicular, one must have the negative reciprocal of the other.

In this case, line b and c are parallel, and they have the same slope, but different y-intercepts.

However, none of the lines are perpendicular, as -1/3x is not the negative reciprocal of 1.5x, or 3/2x.

<h3><u>B and C are parallel, no perpendicular lines.</u></h3>

8 0

3 years ago

PLEASE helpp me in my homework plsssssss

7nadin3 [17]

No, she will not have enough. If you estimate the amount of money it will cost for the turkey sandwich and the large drink, it will cost about $7. She will only have $6.25 after admission costs.

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3 years ago

What occurs at mid-ocean ridges?

leva [86]

Answer:

A midocean ridge or midoceanic ridge is an underwater mountain range, formed by plate tectonics. This uplifting of the ocean floor occurs when convection currents rise in the mantle beneath the oceanic crust and create magma where two tectonic plates meet at a divergent boundary.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Write an expression for the 12th partial sum of the series 3/2+7/3+19/6+... using summation notation

lapo4ka [179]

Answer:

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=73$

Step-by-step explanation:

$First\ term\ of\ the\ series(a_1)=\frac{3}{2}\\\\Second\ term\ of\ the\ series(a_2)=\frac{7}{3}\\\\Third\ term\ of\ the\ series(a_3)=\frac{19}{6}\\\\a_2-a_1=\frac{7}{3}-\frac{3}{2}=\frac{5}{6}\\\\a_3-a_2=\frac{19}{6}-\frac{7}{3}=\frac{5}{6}\\\\Hence\ it\ is\ an\ Arithmetic\ Series\ with\ first\ term=\frac{3}{2}\ and\ constant\ difference=\frac{5}{6}$

$a_1=\frac{3}{2}+0\times \frac{5}{6}\\\\a_2=\frac{3}{2}+1\times \frac{5}{6}\\\\a_3=\frac{3}{2}+2\times \frac{5}{6}\\\\.\\.\\.\\a_n=\frac{3}{2}+(n-1)\times \frac{5}{6}\\\\S_n=a_1+a_2+a_3+......+a_n\\\\S_n=(\frac{3}{2}+0\times \frac{5}{6})+(\frac{3}{2}+1\times \frac{5}{6})+(\frac{3}{2}+2\times \frac{5}{6})+....+(\frac{3}{2}+[n-1]\times \frac{5}{6})\\\\S_n=\sum_{i=1}^n [\frac{3}{2}+(i-1)\times \frac{5}{6}]\\\\S_n=(\frac{3}{2}+\frac{3}{2}+\frac{3}{2}+...n\ times)+\frac{5}{6}(1+2+3+4+...+(n-1))\\\\$