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AlexFokin [52]
3 years ago
13

Which of these questions are equivalent to 1/4

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
7 0
B) 2/8 that’s the answer :p
alex41 [277]3 years ago
7 0
It would be B 2/8 !!!!!
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(1 pt) Let an=n+1n+3. Find the smallest number M such that: (a) |an−1|≤0.001 for n≥M M= 1997 (b) |an−1|≤0.00001 for n≥M M= 20000
xenn [34]

We want to prove

\displaystyle\lim_{n\to\infty}\frac{n+1}{n+3}=1

which is akin to saying that, for any given \varepsilon>0, we guarantee that

\left|\dfrac{n+1}{n+3}-1\right|

for all n exceeding some threshold N=N(\varepsilon).

We want to end up with

\left|\dfrac{n+1}{n+3}-1\right|=\left|-\dfrac2{n+3}\right|=\dfrac2{n+3}

\implies\dfrac{n+3}2>\dfrac1\varepsilon\implies n>\dfrac2\varepsilon-3

which suggests that we guarantee that a_n is arbitrarily close to 1 if N=\left\lceil\dfrac2\varepsilon-3\right\rceil. (Take the ceiling to ensure N is a natural number.)

Now for the proof: Let \varepsilon>0 be given. Then for n>N=\left\lceil\dfrac2\varepsilon-3\right\rceil we have

n>\left\lceil\dfrac2\varepsilon-3\right\rceil\le\dfrac2\varepsilon-3\implies\dfrac2{n+3}

QED

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4 years ago
(2x²+6x-3)+(3x²-8x-6)​
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