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elena-14-01-66 [18.8K]
3 years ago
13

ASAP GEO PROBLEM HELP NEEDED QUICK

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
4 0

Answer:

See below.

Step-by-step explanation:

The converse of the Pythagorean Theorem tells us that if the sum of the square of the two shorter lengths is equivalent to the square of the longest length, then the triangle is indeed a right triangle.

We have the side lengths (x²-1), (2x), and (x²+1).

We can see that our hypotenuse will be (x²+1), since it will always yield the largest value for x.

So, we can use the Pythagorean Theorem:

a^2+b^2=c^2

Substitute (x²-1) and (2x) for a and b, and substitute (x²+1) for c:

(x^2-1)^2+(2x)^2\stackrel{?}{=}(x^2+1)^2

Square each expression:

(x^4-2x^2+1)+(4x^2)\stackrel{?}{=}(x^4+2x^2+1)

Combine like terms:

x^4+(-2x^2+4x^2)+1\stackrel{?}{=}(x^4+2x^2+1)

Add:

x^4+2x^2+1\stackrel{\checkmark}{=}x^2+2x^2+1

We can see that the resulting equations are equivalent, proving that the triangle is indeed a right triangle.

And we're done!

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Answer:

<h3>\frac{\sqrt{24}- \sqrt{54} }{\sqrt{6}} = -1   </h3><h3>\sqrt{\frac{9}{20}*\frac{10\sqrt{2} }{3\sqrt{5} } = 1.4142</h3><h3>\frac{10\pi\sqrt{2}-8\pi\sqrt{2}}{2\sqrt{2}}  = π =3.14159</h3><h3>\pi\sqrt{\frac{5}{3}}\cdot\pi\sqrt{\frac{3}{5}} = π² = 9.8696</h3>

Explanation:

1.) Rewrite √24 = \sqrt{4*6} = 2\sqrt{6}   Rewrite √54 =\sqrt{9*6}= 3\sqrt{6}

Divide both terms by the denominator; √6 cancels. 2-3 = -1

2.) Rewrite as \frac{3}{2\sqrt{5}} ×\frac{10\sqrt{2}}{3\sqrt{5}}  The 3's cancel.  10/2 = 5√2 in the numerator.

√5 × √5 = 5 in the denominator.  The 5's cancel.

That leaves √2 ≈1.4142

3.) Divide the terms in the numerator by the term in the denominator.

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Subtract and we are left with π = 3.14159

4.) \pi\sqrt{\frac{5}{3}}\cdot\pi\sqrt{\frac{3}{5}}  The square roots are reciprocals. They multiply to 1

We are left with π × π = π² ≈  9.8696

<h3> </h3>

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Step-by-step explanation:

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The answer to your question is: 48.6 ft

Step-by-step explanation:

See the picture below

Use the Thales's theorem to solve this exercise

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