Do you know how to solve this??
Using the rectangular route Mike rides 12 miles. If he rides diagonally the distance is √2²+10²=√4+100=√104.
The difference between the two routes is 12-√104=1.80 miles approximately.
Y = -3x + 13
Steps and the graph are on paper
<h3>
Answer: Q = 8</h3>
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Explanation:
The left hand side of the first equation is x-3y
The left hand side of the second equation is 2x-6y = 2(x-3y). Note how it's simply double of the first expression x-3y
If we multiply both sides of the first equation by 2, we get
x-3y = 4
2(x-3y) = 2*4
2x-6y = 8
Meaning that 2x-6y = 8 is equivalent to x-3y = 4. Both produce the same line leading to infinitely many solutions. Each solution will lay along the line x-3y = 4.
We can say each solution is in the set {(x,y): x-3y = 4}
Which is the same as saying each solution is of the form (3y+4,y)
Answer:
A) ![\left[\begin{array}{cc}0&-1\\1&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0%26-1%5C%5C1%260%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The rotation matrix for a clockwise rotation through angle θ is given by ...
![M=\left[\begin{array}{cc}\cos{(\theta)}&-\sin{(\theta)}\\\sin{(\theta)}&\cos{(\theta)}\end{array}\right]](https://tex.z-dn.net/?f=M%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Ccos%7B%28%5Ctheta%29%7D%26-%5Csin%7B%28%5Ctheta%29%7D%5C%5C%5Csin%7B%28%5Ctheta%29%7D%26%5Ccos%7B%28%5Ctheta%29%7D%5Cend%7Barray%7D%5Cright%5D)
When θ = 90°, the matrix becomes the one in choice A).
