Just apply the addition formulas:
sin(x+y) = sinx cosy + cosx siny
sin(x-y) = sinx cosy - cosx siny
now subtract. done.
or, apply the sum-to-product formula directly: sinA-sinB = 2sin((A-B)/2)cos((A+B)/2)
so, letting A=x+y and B=x-y
sin(x+y)-sin(x-y) = 2sin(((x+y)-(x-y))/2) cos(((x+y)+(x-y))/2)
= 2 siny cosx
but then, the sum-to-product formula is just based on the addition formulas anyway, so what'd you expect?
So I assume you mean a rectangular field with two semicircular ends...
c=.4(160*50+π25^2)
c=.4(8000+625π)
c=320+250π
c≈$1105.40 to nearest cent
(-3/2, 7/2)
-3/2+7/2=2
7/2=-3/2+5
