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yKpoI14uk [10]
2 years ago
14

I'm having trouble figuring out what the difference between two positive numbers are. The numbers are 3.9 and 8.3 and I'm not su

re what I'm supposed to do. Subtract both numbers? If so, in hat order?
Mathematics
2 answers:
Tju [1.3M]2 years ago
8 0
To find the difference between these numbers you need to subtract 8.3 - 3.9
and that equals 4.4<span />
3241004551 [841]2 years ago
3 0
You will subtract both numbers in that order that it is written. If it was put as 3.9 and 8.3, then subtract the 2 numbers.

Since 3.9 is less then 8.3, this will be a little tricky. I will show you a hack I use.

Since we know 3.9 is less then 8.3, that means the answer will be a negative answer.

I subtract 8.3-3.9 first, which is 4.4.

Since it is 3.9 that is first, 4.4 will change to negative 4.4.

-4.4 will be your answer.

Hope this helped, and please mark brainliest! :)
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3 0
3 years ago
HELP!!!!PLS!!
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Answer:

12 units

Step-by-step explanation:

(-7,-6)

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4 0
3 years ago
Which pair of ratios form a proportion?
kumpel [21]
B.) 10:18 and 25:45
You can simplify this.
Divide the first part by 2.
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5 0
3 years ago
The sum of the first two terms of an infinite GP is 6 and each term is 5 times the sum of the succeeding termsthen the second te
kozerog [31]

Answer:

\dfrac{6}{7}.

Step-by-step explanation:

It is given that the sum of first two terms of an infinite GP is 6.

nth term of a GP is

a_n=ar^{n-1}

a+ar=6     ...(1)

Each term is 5 times the sum of the succeeding terms.

a_n=5(a_{n+1}+a_{n+2}+...+\infty)

ar^{n-1}=5(ar^n+ar^{n+1}+...+\infty)

ar^{n-1}=5ar^n(1+r+r^2+...+\infty)

Divide both sides by a.

r^{n-1}=5r^n(\dfrac{1}{1-r})    [\text{Sum of infinite GP}=\dfrac{a}{1-r}]

\dfrac{r^n}{r}=\dfrac{5r^n}{1-r}

\dfrac{1}{r}=\dfrac{5}{1-r}

1-r=5r

1=6r

\dfrac{1}{6}=r

The common ratio is 1/6.

Put r=1/6 in (1).

a+a(\dfrac{1}{6})=6

6a+a=36

7a=36

a=\dfrac{36}{7}

Second term ar=\dfrac{36}{7}\times \dfrac{1}{6}=\dfrac{6}{7}

Therefore, the second term is \dfrac{6}{7}.

4 0
2 years ago
A 33 - m tall building casts a shadow. The distance from the top of the building to the tip of the shadow is 37 m . Find the len
ArbitrLikvidat [17]
This is Pythagorean theorem, a^2+b^2=c^2 , a = 33 and c = 37 so b^2 + 1089 = 1369 , b^2 = 280 , b = 16.73m
5 0
3 years ago
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