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3 years ago

How many groups of 4/5 in 2

1 answer:

3 0

2 1/2 groups of 4/5 fill in two. Another way of saying that is what is 2 divided by 4/5. The answer is 2 1/2.
~Deceptiøn

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Find the perimeter RST. Round answer to the nearest tenth<br> Show all the work

kow [346]

Answer:

35.1 units

Step-by-step explanation:

Imagine a right-angled triangle with RS as hypotenuse. The base would be 3 units and the height would be 6 units. By Pythagorus:

RS²=3²+6²

RS= $\sqrt{45}$ ≈6.7 units

Imagine a right-angled triangle with RT as hypotenuse. The base would be 9 units and the height would be 12 units. By Pythagorus:

RT²=9²+12²

RT= $\sqrt{225}$ = 15 units

Imagine a right-angled triangle with TS as hypotenuse. The base would be 12 units and the height would be 6 units. By Pythagorus:

TS²=12²+6²

TS= $\sqrt{180}$ ≈13.4 units

Perimeter=RS+RT+TS

=6.7+15+13.4

=35.1 units

6 0

3 years ago

Determine if the statements below are true or false. Justify your answer. (a) If a fair coin is tossed many times and the last e

denis23 [38]

Answer:

(a) is False (b) is true (c) is true

Step-by-step explanation:

4 0

2 years ago

Given that x = -2 - 3i and y = 4 + 2i , Match The Expressions.

shtirl [24]

Answer:

$3y-2x=16+12i$

$-3x \cdot y=6+48i$

$x \cdot 2y=-4-32i$

$x-y=-6-5i$

Step-by-step explanation:

Given:

$x=-2-3i$

$y=4+2i$

---

1st problem:

$3y-2x$

$3(4+2i)-2(-2-3i)$

Distribute:

$12+6i+4+6i$

Combine like terms:

$16+12i$

---

2nd problem:

$-3x \cdot y$

$-3(-2-3i) cdot (4+2i)$

$-3(-2-3i)(4+2i)$

Distribute -3 to first factor:

$(6+9i)(4+2i)$

Use foil to simplify:

$24+12i+36i+18i^2$

Replace $i^2$ with -1:

$24+48i-18$

Combine like terms:

$6+48i$

---

3rd problem:

$x \cdot 2y$

$(-2-3i) \cdot 2(4+2i)$

Distribute 2 to the second factor:

$(-2-3i) \cdot (8+4i)$

$(-2-3i)(8+4i)$

Use foil to simplify:

$-16-8i-24i-12i^2$

Replace $i^2$ with -1:

$-16-32i+12$

Combine like terms:

$-4-32i$

----

4th problem:

$(-2-3i)-(4+2i)$

Distribute:

$-2-3i-4-2i$

Combine like terms:

$-2-4-3i-2i$

Simplify:

$-6-5i$

6 0

3 years ago

Read 2 more answers

Consider the cubic function f(x) = x^3 + ax^2 + bx + 4 where (a) and (b) are constants. When f(x) is divided by x-3, the remaind

Debora [2.8K]

Answer:

see explanation

Step-by-step explanation:

Using the Remainder theorem

If f(x) is divided by (x - h) then f(h) = remainder, thus

f(3) = 3³ + a(3)² + b(3) + 4 = 10, that is

27 + 9a + 3b + 4 = 10

9a + 3b + 31 = 10 ( subtract 31 from both sides )

9a + 3b = - 21 → (1)

f(- 1) = (- 1)³ + a(- 1)² + b(- 1) + 4 = 6, that is

- 1 + a - b + 4 = 6

a - b + 3 = 6 ( subtract 3 from both sides )

a - b = 3 → (2)

Rearrange (2) expressing a in terms of b

a = 3 + b → (3)

Substitute a = 3 + b into (1)

9(3 + b) + 3b = - 21 ← distribute and simplify left side

27 + 9b + 3b = - 21

12b + 27 = - 21 ( subtract 27 from both sides )

12b = - 48 ( divide both sides by 12 )

b = - 4

Substitute b = - 4 into (3)

a = 3 - 4 = - 1

Hence a = - 1 and b = - 4

8 0

2 years ago

10x10x10x10x10x10x10 in word form

Vsevolod [243]

Answer:

10,000,000

Step-by-step explanation:

ten million

5 0

3 years ago

Read 2 more answers