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Art [367]
4 years ago
8

How many groups of 4/5 in 2

Mathematics
1 answer:
Veseljchak [2.6K]4 years ago
3 0
2 1/2 groups of 4/5 fill in two. Another way of saying that is what is 2 divided by 4/5. The answer is 2 1/2.
~Deceptiøn
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There are 8 sophomores on the academic team. At the last competition, they each took the math test. Their scores were 82%, 92%,
Sav [38]

Answer:

79%

Step-by-step explanation:

To find the median, you need to arrange the numbers in ascending order. Than pick the middle number. If there are two middle numbers then you add them together and then divide by 2.

3 0
3 years ago
I lowkey need help on number five like I don’t get it . Am I doing something wrong cause I feel like I am ? And which equation w
Tpy6a [65]

43,802 round to tha nearest thounsand

5 0
3 years ago
A garden is made up of two squares and a quarter circle. What is the area of the garden?
Elanso [62]

9514 1404 393

Answer:

  100.27 ft^2

Step-by-step explanation:

The area of each square is ...

  A = s^2 = (6 ft)^2 = 36 ft^2

The area of the 1/4 circle is ...

  A = 1/4πr^2 = 1/4π(6 ft)^2 = 9π ft^2 ≈ 28.27 ft^2

__

The area of the garden is the sum of the areas of the quarter circle and the two squares:

  A = 28.27 ft^2 + 2×36 ft^2 = 100.27 ft^2

The area of the garden is about 100.27 square feet.

7 0
3 years ago
within a kiambu county,students were randomly assigned to one of two mathematics teachers.Mrs.Elite and Mrs. Bright. After the a
DerKrebs [107]

Using the t-distribution, as we have the standard deviation for the samples, it is found that since the absolute value of the test statistic is greater than the critical value, we reject the claim that Mrs.Elite and Mrs. Bright are equally effective teachers.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if they are equally effective teachers, that is, the subtraction of their means is 0, hence:

H_0: \mu_1 - \mu_2 = 0

At the alternative hypothesis, we test if they are not equally effective teachers, that is, the subtraction of their means is not 0, hence:

H_1: \mu_1 - \mu_2 \neq 0

<h3>What is the distribution of the differences?</h3>

For Mrs. Elite, we have that:

\mu_1 = 78, \sigma_1 = 10, n_1 = 30, s_1 = \frac{10}{\sqrt{30}} = 1.82574

For Mrs. Bright, we have that:

\mu_2 = 85, \sigma_2 = 15, n_2 = 25, s_2 = \frac{15}{\sqrt{25}} = 3

For the distribution of differences, we have that:

\overline{x} = \mu_1 - \mu_2 = 78 - 85 = -7

s = \sqrt{s_1^2 + s_2^2} = \sqrt{1.82574^2 + 3^2} = 3.5119

<h3>What is the test statistic?</h3>

The test statistic is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{-7 - 0}{3.5119}

t = -1.99

Considering a<em> two-tailed test</em>, as we are testing if the mean is different of a value, with 30 + 25 - 2 = <em>53 df and a significance level of 0.1</em>, the critical value is of |t^{\ast}| = 1.6741.

Since the absolute value of the test statistic is greater than the critical value, we reject the claim that Mrs.Elite and Mrs. Bright are equally effective teachers.

To learn more about the t-distribution, you can take a look at brainly.com/question/13873630

3 0
3 years ago
Y + 4 = x - 3<br> how do I graph this??
Levart [38]
Bggggfffffdfffggvvvvvv
7 0
4 years ago
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