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4 years ago

On the first part of a journey, Alan drove a distance of x km and his car used 6 litres of fuel.

Mathematics

1 answer:

irinina [24]4 years ago

6 0

Answer:

$\frac{600}{x+20}\text{ litres per 100 km}$

Step-by-step explanation:

Given,

The number of litres consumed by car in (x+20) km = 6,

So, number of litres consumed by car in 1 km = $\frac{6}{x+20}$ ,

Now, number of litres consumed by car in 100 km = 100 × litres consumed by car in 1 km

$=100\times \frac{6}{x+20}$

$=\frac{600}{x+20}$

Hence, the rate of fuel used by his car would be $\frac{600}{x+20}$ litres per 100 km.

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9 tenths - 3 tenths =

amm1812

9 tenths - 3 tenths = 6 tenths. this is true the same way that 9 minus 3 = 6. In reality the tenths make both numbers decimals, but in this case the "tenths" is just a classification of the number and it doesn't effect the answer.

3 0

3 years ago

Read 2 more answers

Please help with the questions in the image

polet [3.4K]

Answer:

(a) C(d) = 270 + 0.20d
(b) C(1800) = 630
(c) see attached (lower right graph). The slope represents the cost (in dollars) per mile.
(d) It represents the fixed cost (amount she pays even if she does not drive)
(e) the cost increases as the number of miles driven increases

Step-by-step explanation:

(a) You are given two points, (d, C) = (360, 342) and (780, 426). The two-point form of the equation for a line can be helpful.

... y = (y2 -y1)/(x2 -x1)(x -x1) +y1

Using the given points and variables, ...

... C = (426 -342)/(780 -360)(d -360) +342

... C = (84/420)(d -360) +342

... C = 0.20d +270 . . . . the equation for cost as a function of miles driven

(b) Fill in the value for d and do the arithmetic.

... C = 0.20·1800 +270 = 360 +270 = 630

(c) The slope of the curve is (change in dollars)/(change in miles) = $/mile, the cost of each mile driven. (It is $0.20 per mile.)

(d) The C-intercept is C(0) = cost for 0 miles driven. (It is $270.)

(e) Both your own experience and the problem statement tell you that the cost of vehicle operation varies with miles driven. If nothing else, you need to pay more for gas the farther you drive.

(In real life, you don't expect the model to be exactly linear, becasue you get a large jump in cost when you reach certain maintenance interval miles: 15,000, 30,000, and so on.)

7 0

3 years ago

Hey:) can you please help me posted picture of question

mr Goodwill [35]

The top row contains the product of $x^{2}$ with each term of the expressions $x^{6}+ x^{4}+ x^{2}$ and bottom row contains the product of -1 with each term of expression $x^{6}+ x^{4}+ x^{2}$ .

The final result will be the sum of terms of both rows as shown below:

$( x^{6}+ x^{4} + x^{2} )( x^{2} -1) \\ \\ 
= x^{2} ( x^{6}+ x^{4} + x^{2} )-1( x^{6}+ x^{4} + x^{2} ) \\ \\ 
= x^{8}+ x^{6}+ x^{4}- x^{6}- x^{4}- x^{2} \\ \\ 
= x^{8}- x^{2}$

So the correct answer is option D

8 0

3 years ago

Help please ! Need the answers

son4ous [18]

Answer:

$x=\frac{-5+\sqrt{13}}{6} or x=\frac{-5-\sqrt{13}}{6} (decimal: x=-0.23240 , x=-1.43425)$