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3 years ago

Find the variable x.

Mathematics

1 answer:

grandymaker [24]3 years ago

5 0

Answer:

x = 7

Step-by-step explanation:

The inscribed angle (5x - 3) is equal to half the measure of the intercepted arc

5x - 3 = 0.5(9x + 1) ← multiply both sides by 2

10x - 6 = 9x + 1 ( subtract 9x from both sides )

x - 6 = 1 ( add 6 to both sides )

x = 7

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Find the probability P(z < 0.37) using the standard normal distribution.

dimaraw [331]

Answer:

0.6443

Step-by-step explanation:

Given the that:

P(Z < 0.37) ; using a standard normal distribution :

The probability can be obtained using several methods :

Using a standard normal distribution table ;

P(Z < 0.37) = obtain the value at the intersection where 0.3 is on the vertical axis and 0.07 on the horizontal axis of the Z distribution table

Hence,

P(Z < 0.37) = 0.6443

4 0

3 years ago

Two third of a number is 5 more than half of its what is the number

weeeeeb [17]

I need help on that to

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%282%20-%206x%29%20-%204%28x%20%20%2B%20%20%5Cfrac%7B3%7D%7B2%7D%29%20

Art [367]

Answer:

x=-2

Step-by-step explanation:

1/2(2-6x)-4(x+3/2)=-(x-3)+4

(1-3x)-4x-6=-x+3+4

-7x-5=-x+7

Tranpose

-7x+x=5+7

-6x=12

Divide by -6

x=-2

4 0

3 years ago

Shade the model to 0.5 x 0.3

stellarik [79]

What model? also it would be 1/2 and 1/3

6 0

3 years ago

Read 2 more answers

Show both decimal places (5.06).

lilavasa [31]

a. the cost of a call for six minutes is 0.70.

b.the cost of a 14-minute call is 2.62.

c.the cost of a 9 ½2-minute call is 1.66.

given that

rate schedule for an m-minute call from any of its pay phones 0.70.

c(m) = 0.70 when m<=6

c(m) = 0.70+ 0.24(m-6) when m>6 & m is an integer

c(m) = 0.70+0.24((m-6)+1) when m>6 & m is not an integer.

a. to find the cost of a call for six minutes.

already given that c(m) =0.70 when m=6.

Therefore, the cost of a call for six minutes is 0.70.

b. to find the cost of a 14-minute call.

according to given information

$c(14) = 0.70 + 0.24(m - 6) \\ c(14) = 0.70 + 0.24(14 \: - 6) \\c(14) = 0.70 + (0.24 \times 14) - (0.24 \times 6) \\c(14) = 0.70 + (3.36 - 1.44) \\ c(14) = 0.70 + 1.92 \\ c(14) = 2.62$

Therefore,the cost of a 14-minute call is 2.62.

c.to find the cost of a 9 ½2-minute call

according to given information

$c(9 \frac{1}{2} 2) = 0.70 + 0.24((9 \frac{1}{2} 2 - 6) + 1) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.24((9 - 6) + 1) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.24(3+ 1) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.24(4) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.96 \\ c(9 \frac{1}{2} 2) = 1.66$

Therefore,the cost of a 9 ½2-minute call is 1.66.

Learn more about problems on cost of call, refer:

brainly.com/question/16584226

#SPJ9

4 0

1 year ago