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steposvetlana [31]
3 years ago
5

In ΔXYZ, z = 81 cm, ∠Y=139° and ∠Z=6°. Find the length of y, to the nearest 10th of a centimeter.

Mathematics
2 answers:
monitta3 years ago
5 0

Answer:

508.4

Step-by-step explanation:

delta math

Delicious77 [7]3 years ago
3 0

Answer:

508.4

Step-by-step explanation:

This is on delta math

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When are x+3 and 2x equal? When are they not equal? Use your diagrams to explain.
Tanzania [10]
Yes hope this helps :)


4 0
3 years ago
A famous basketball player scored 97 points in a high scool game, breaking a national record. She made 43 more 2-point baskets t
ziro4ka [17]
X - 3pt  baskets  (he reaches 3x points)
y - 2pt baskets  (he reaches 2y points)

We know, that  y=x+43

97 - 1 free throw = 97 - 1 = 96
Sum of points:  96

3x + 2y = 96.   Substitute  to "y"  an expression "x+43" :

3x + 2(x+43)=96
3x+2x+86=96
5x=10    |:5
x=2 

So y=x+43=2+43=45 

He has made 2  three points baskets and 45 two points baskets
8 0
3 years ago
The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth
MAXImum [283]
<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

\twoheadrightarrow \quad\sf{ Length =2(Width)-5}

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\

  • <em>l</em> denotes length
  • <em>b</em> denotes breadth

\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\

\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\

\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\

\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\

\\ \twoheadrightarrow \quad\sf{60= 6b} \\

\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\

\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\

Now, finding the length. According to the question,

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}

\twoheadrightarrow \quad\sf{ \ell=20-5\; m}

\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\

<u>Therefore</u><u>,</u><u> </u><u>length</u><u> </u><u>and</u><u> </u><u>breadth</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>r</u><u>ectangle</u><u> </u><u>is</u><u> </u><u>1</u><u>5</u><u> </u><u>m</u><u> </u><u>and</u><u> </u><u>10</u><u> </u><u>m</u><u>.</u><u> </u>

7 0
3 years ago
Jared hiked a trail that is 12 miles long. He hiked the trail in section that were 1.5
shepuryov [24]
Not sure but it’s probably 8
12 divided by 1.5= 8
6 0
3 years ago
#2
Arturiano [62]

Answer:

We'll use the variable x to represent last year's price. First, we have to set up an equation:

We get this equation because $13.25 is 6% MORE than last year's price, meaning we need to add the original price to the increase. Next, we combine like terms and solve for x:

Last year's price was $12.50.

Step-by-step explanation:

4 0
3 years ago
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