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attashe74 [19]
3 years ago
10

A student gets paid to sell raffle tickets at the school basketball game. He earns $15 a day, plus an extra $0.25 for each raffl

e ticket he sells and $2 for each hour he works at the game. If d = days, r = raffle tickets, and h = hours, what function can he use to calculate his earnings?

Mathematics
2 answers:
ElenaW [278]3 years ago
8 0
Answer is C

T = 15d +r/4 +2h

or

 you can write another way

T = 15d + 0.25r + 2h 
maks197457 [2]3 years ago
4 0

Answer: C. T=15d+\frac{r}{4}+2h

Step-by-step explanation:

Let d = days, r = raffle tickets, and h = hours.

Given: A student earns in a day = $15

Then his earning in d days =$15d

Also, he earns for each riffle = $0.25

Then his earning in for r riffles =$0.25r

And , he earns for each hour he works at the game = $2

Then his earning for h hours = $2h

Then the function he can use to calculate his earnings is given by :_

T=15d+0.25r+2h\\\\\Rightarrow\ T=15d+\frac{1}{4}r+2h

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AlexFokin [52]
Perimeter = (length+width) x 2


Let w units be the width of the rectangle.

Length of the rectangle = 2w

Perimeter:
(2w+w) x 2 = 60

(3w)2 = 60

6w = 60

w = 10


Area:
2(10) x 10

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4 0
2 years ago
You need to write an essay that has at least 500 words. You have written 285 words so far. Write and solve an inequality that re
BabaBlast [244]

Answer:

The minimum number of words left to write is 215

Step-by-step explanation:

Let

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we know that

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w+285\geq 500

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Subtract 285 both sides

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4 0
3 years ago
Please help with any of this Im stuck and having trouble with pre calc is it basic triogmetric identities using quotient and rec
german

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

#3

Let's start with sin here. \frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}} Therefore, because sin is y/r, r = \sqrt{5} and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = \frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}

#4

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = 4\sqrt{2}. Now, to find csc, we have to do r/y.

csc = \frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

#5

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = \sqrt{7/16} = \frac{\sqrt{7}}{4}

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = -\sqrt{7/9} = \frac{-\sqrt{7}}{3}

#6

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = (\frac{-\sqrt{6}}{2})^{2}

1 + cot^2 = 6/4

cot^2 = 2/4

cot = \frac{\sqrt{2}}{2}

tan = \sqrt{2}

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

(\frac{2}{\sqrt{2}})^2 + 1 = sec^2

4/2 + 1 = sec^2

2 + 1 = sec^2

sec^2 = 3

sec = -\sqrt{3}

cos = \frac{-\sqrt{3}}{3}

Hope this helps!! :)

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