Answer:
the answer is b i thinkk.
Answer:
24s^2, 54s^2, 96s^2
Step-by-step explanation:
Let s represent the initial side length of the cube. Then the area of each face of the cube is A = 6s^2 (recalling that the area of a square of side length s is s^2).
a) Now suppose we double the side length. The total area of the 6 faces of the cube will now be A = 6(2s)^2, or 24s^2 (a 24 times larger surface area),
b) tripled: A = 6(3s)^2 = 54x^2
c) quadrupled? A = 6(4s)^2 = 96s^2
Answer: A B
Group 1 0.25 0.75
Group 2 0.44 0.56
Step-by-step explanation:
Since we have given that
Number of people of A in group 1 = 15
Number of people of B in group 1 = 45
Total number of people in group 1 is given by
![15+45=60](https://tex.z-dn.net/?f=15%2B45%3D60)
Relative frequency of people of A in Group 1 is given by
![\frac{15}{60}=0.25](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B60%7D%3D0.25)
Relative frequency of people of B in Group 1 is given by
![\frac{45}{60}=0.75](https://tex.z-dn.net/?f=%5Cfrac%7B45%7D%7B60%7D%3D0.75)
Similarly, Number of people of A in group 2 = 20
Number of people of B in group 2 = 25
Total number of people in group 2 is given by
![20+25=45](https://tex.z-dn.net/?f=20%2B25%3D45)
Relative frequency of people of A in Group 2 is given by
![\frac{20}{45}=0.44](https://tex.z-dn.net/?f=%5Cfrac%7B20%7D%7B45%7D%3D0.44)
Relative frequency of people of B in Group 2 is given by
![\frac{25}{45}=0.56](https://tex.z-dn.net/?f=%5Cfrac%7B25%7D%7B45%7D%3D0.56)
Hence, A B
Group 1 0.25 0.75
Group 2 0.44 0.56