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Verdich [7]
4 years ago
13

If 3x +b = c, what is the value of x in terms of c and b?

Mathematics
1 answer:
german4 years ago
3 0

Answer:

x=(c-b)/3

Step-by-step explanation:

we have

3x+b=c

Solve for x

That means -----> Clear variable x

Subtract b both sides

3x+b-b=c-b

3x=c-b

Divide by 3 both sides

x=(c-b)/3

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A triangle shaped paper’s height is 18 cm and width is 10 cm. Find the hypotenuse of the paper.
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Answers fast please. 1.) y=x−63x+2y=8 Use the substitution method. A.) (4, −2) B.) (14, 8) C.) (0, −6) D.) (3, −3) 2.) What is t
GrogVix [38]

<u>QUESTION 1</u>

The given system of equation is

y=x-6...eqn1

and


3x+2y=8...eqn2


Let us substitute equation (1) into equation (2) to get,

3x+2(x-6)=8


We expand the bracket to get,

3x+2x-12=8


We simplify to get.

5x-12=8


We group like terms to get

5x=8+12

\Rightarrow 5x=20

\Rightarrow x=4


We now substitute x=4 in to equation (1) to obtain,


y=4-6=-2


The correct answer is option A.


<u>QUESTION 2</u>

The given system of equations is

y-x=9...eqn1


and

10+2x=-2y...eqn2

We make y the subject in equation (2) to get,

y=-x-5..eqn3


We put equation (3) into equation (1) to obtain,


-x-5-x=9


We group like terms to get,

-x-x=9+5


This implies that,

-2x=14


We divide through by -2 to get,

x=-7


Hence the x-coordinate is -7



<u>QUESTION 3</u>

The given system is

y=3x-1..eqn1


and


x-y=-9...eqn2

We make x the subject in equation (2) to get,

x=y-9...eqn3


We put equation (3) into equation (1) to obtain,


y=3(y-9)-1


We expand the bracket to get,


y=3y-27-1


Group like terms to get,


y-3y=-27-1


We simplify to get;

-2y=-28


This implies that,

y=14


Therefore the y-coordinate is 14.

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