Ask question

Ask question

All categories

3 years ago

8

Cate muchii are un cilindru?

1 answer:

fenix001 [56]3 years ago

5 0

2.............................................

You might be interested in

Which equation has a graph that passes through the points at (0,5) and (-3,-4)?

Roman55 [17]

Answer:

$y = 3x + 5$

Step-by-step explanation:

We are asked the equation of the graph which passes through the points at (0,5) and (-3,-4).

Now, we know that the equation of a straight line passing through the points ( $x_{1},y_{1}$ ) and ( $x_{2},y_{2}$ ) is given by

$\frac{y - y_{1}}{y_{1} - y_{2}} = \frac{x - x_{1}}{x_{1} - x_{2}}$ .

So, in our case ( $x_{1},y_{1}$ ) ≡ (0,5) and ( $x_{2},y_{2}$ ) ≡ (-3,-4)

Therefore, the equation of the straight line will be

$\frac{y - 5}{5 - (- 4)} = \frac{x - 0}{0 - (- 3)}$

⇒ $y - 5 = \frac{9}{3}x$

⇒ $y = 3x + 5$ (Answer)

4 0

3 years ago

Please help! i dont understand

kvv77 [185]

QUESTION 1

The given inequality is

$y\leq x-3$ and $y\geq -x-2$ .

If (3,-2) is a solution; then it must satisfy both inequalities.

We put x=3 and y=-2 in to both inequalities.

$-2\leq 3-3$ and $-2\geq -3-2$ .

$-2\leq 0$ :True and $-2\geq -5$ :True

Both inequalities are satisfied, hence (3,-2) is a solution to the given system of inequality.

QUESTION 2

The given inequality is

$y\:>\:-3x+3$ and $y\:>\: x+2$ .

If (1,4) is a solution; then it must satisfy both inequalities.

We put x=1 and y=4 in to both inequalities.

$4\:>\:-3(1)+3$ and $4\:>\: 1+2$ .

$4\:>\:0$ :True and $4\:>\: 3$ :True

Both inequalities are satisfied, hence (1,4) is a solution to the given system of inequality.

Ans: True

QUESTION 3

The given inequality is

$y\leq 3x-6$ and $y\:>\: -4x+2$ .

If (0,-2) is a solution; then it must satisfy both inequalities.

We put x=0 and y=-2 in to both inequalities.

$-2\leq 3(0)-6$ and $-2\:>\: -4(0)+2$ .

$-2\leq -6$ :False and $-2\:>\:2$ :False

Both inequalities are not satisfied, hence (0,-2) is a solution to the given system of inequality.

Ans:False

QUESTION 4

The given inequality is

$2x-y\:$ and $x+y\:>\:-1$ .

If (0,3) is a solution; then it must satisfy both inequalities.

We put x=0 and y=3 in to both inequalities.

$2(0)-3\:$ and $0+3\:>\:-1$ .

$-3\:$ :True and $3\:>\:-1$ : True

Both inequalities are satisfied, hence (0,3) is a solution to the given system of inequality.

Ans:True

QUESTION 5

The given system of inequality is

$y\:>\:2x-3$ and $y\:$ .

If (-3,0) is a solution; then it must satisfy both inequalities.

We put x=-3 and y=0 in to both inequalities.

$0\:>\:2(-3)-3$ and $0\:$ .

$0\:>\:-9$ ;True and $0\:$ :True

Both inequalities are satisfied, hence (-3,0) is a solution to the given system of inequality.

Ans:True

3 0

2 years ago

On a family trip, natalie counted 3 groups of 5 motocycles and additonal 7 solo motocycles. write an expression for the number o

timama [110]

3×5=× would be the answer

4 0

2 years ago

Read 2 more answers

Can you please give me correct answer

dybincka [34]

Answer:

wait wait explain on what i need to do

Step-by-step explanation:

7 0

3 years ago

Find an explicit formula for g(n)

Elina [12.6K]

Answer:

g(n) = 2n + 49

Step-by-step explanation:

The explicit formula for an arithmetic sequence is

g(n) = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given the recursive formula

g(n) = g(n - 1) + 2 ← with d = 2 and a₁ = 51, then

g(n) = 51 + 2(n - 1) = 51 + 2n - 2 = 2n + 49 ← explicit formula

6 0

3 years ago