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deff fn [24]
3 years ago
12

CAN I GET SOME HELP PLEASE!!

Mathematics
1 answer:
andreev551 [17]3 years ago
3 0
With what the picture of the paper????

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HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP
pickupchik [31]
B. the diagonals are congruent - the graph represents two equal, parallel lines, making the two segments congruent
3 0
3 years ago
State the angle relationship and state the measure of each angle indicated that makes lines u and v
vlabodo [156]

Answer:

Q9. ?=53° (corr angles, u//v)

Q10. ?=58° (alt angles, u//v)

7 0
3 years ago
What form of a linear equation is y - 6 = -4(x + 2) ?
Softa [21]

Answer:

Point slope form

Step-by-step explanation:

Given

y - 6 = -4(x + 2)

Required

Determine the form of linear equation

A linear has just three forms:

1. The slope intercept form.: This is always in form of y = mx + b

2. The point slope form: This is always in form of y - y_1 = m(x - cx_1(

2. The standard form: This is always in form of Ax + Bxx = c

<em>By comparison, the three forms with the question, we can see that option B answers the question.</em>

3 0
3 years ago
Alicia wants to bake a cake with ⁹/10 grams of flour.However,she only has ⅓ grams of flour she needs.How much does she have?
natali 33 [55]

Answer:

We know that:

She needs 9/10 grams of flour for the cake (this quantity does not make a lot of sense, maybe is written incorrectly, but is the only info we have, so let's solve the problem with this)

She only has 1/3 of the amount she needs.

How much flour does she have?

Well, she needs 9/10 grams, and she has one-third of that.

Then she has (1/3) times (9/10) grams, this is:

F = (1/3)*(9/10) grams

F = (1*9)/(3*10) grams

F = 9/30 grams

That is the amount of flour that she has.

6 0
3 years ago
Add three data values to the following data set so the mean increases by 10 and the median does not change. {42, 37, 32, 29, 20}
aksik [14]
Sum of the numbers in the set: 42+37+32+29+20 =160

Current mean: 160/5 = 32

Median = the valvue of the middle = 32.

New mean: 32+10= 42.

Sum of numbers in the new set = 42*8 = 336

Difference: 336 - 160 = 176

I want to include 32, so that the new median stays in 32.

So the other two numbers must add 176 - 32 = 144

I will use a smaller number than 32 and the other greater (again in order to  keep the same median.

I will choose 28 and 144 - 28 = 116.

So my three new numbers are 28, 32 and 116 and the new set is {116, 42, 37, 32, 32, 29,28, 20}

Checking:

Sum of the terms: 116+42+37+32+32+29+28+20 = 336

Mean = 336 / 8 = 42, which is 10 more than the original mean.

And the new median is (32+32)/2 = 32. The same of the original set.
8 0
3 years ago
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