First find the radius of circle A. You know that the equation is r^2*pi, so just divide both by pi.
r^2*pi=16pi
/pi /pi
r^2=16
R is 4. That means that circle B is 2, since its radius is half that of circle A.
C=pi2r
C=pi2(2)
C=pi4
C=4pi
The answer is 4pi.
Answer:
tan(Sin^-1 x/2)= 
Step-by-step explanation:
Let sin^-1 x/2= θ
then sinθ= x/2
on the basis of unit circle, we have a triangle with hypotenuse of length 1, one side of length x/2 and opposite angle of θ.
tan(Sin^-1 x/2) = tanθ
tanθ= sinθ/cosθ
as per trigonometric identities cosθ= √(1-sin^2θ)
tanθ= sinθ/ √(1-sin^2θ)
substituting the value sinθ=x/2 in the above equation
tanθ= 
now substituting the value sin^-1 x/2= θ in above equation
tan(sin^-1 x/2) = 
!
Answer:
p = 3, p = 5
Step-by-step explanation:
Express 150 as a product of prime factors, that is
150 = 2 × 3 × 5 × 5
Thus 2 odd factors of 150 are 3 and 5
The possible values of p are 3 and 5
We look for the linear function of the table:
y-yo = m (x-xo)
Where,
m = (0-12) / (6-0)
m = (- 12) / (6)
m = -2
(xo, yo) = (0, 12)
Substituting:
y-12 = -2 (x-0)
Rewriting:
y = -2x + 12
Answer:
The slope is -2, and the y-intercept is 12