QUESTION 12
The given figure has five unequal sides.
The perimeter is the distance around the figure.
So we add all the lengths of the sides of the rectangle to get,

We regroup the like terms to obtain,

This will simplify to give us,


QUESTION 13
The given figure has two pairs of sides that are equal in length and three unequal sides.
The perimeter can be found by adding all the lengths of the sides of the of the figure.
This will give us

We regroup like terms to obtain,

This finally simplifies to ,
.

QUESTION 14
This plane figure has four sides that are equal to 4j and two sides that are equal to 2h.
We add all the lengths of the sides of the plane figure to get,

This will simplify to give us,
-19 to -15 would be a positive 4 difference
19 to 15 = 4 this would be a -4 difference
3 to 7 is a positive 4 difference
-3 to 7 is a difference of 10
so there is 1 with a -4 difference
answer is B.
Answer:
3. 16
Explanation:
Factor the numerator and denominator and cancel the common factors.
Answer:
Bryce is wrong in step 1 because he did not distribute 3 over 5/3
Explanation
Given the steps taken by bryce as shown, we are to find where he made an error

Given the expression;

Step 1:Expand the bracket using the distributive law;
8/3 = 3c + 3(5/3)
<em>Simplify</em>
8/3 = 3c + 15/3
Step 2: Subtract 15/3 from both sides
8/3 - 15/3 = 3c+15/3-15/3
(8-15)/3 = 3c
-7/3 = 3c
Step 3: Multiply both sides by 1/3
-7/3 * 1/3 = 3c * 1/3
-7/9 = c
Swap
c = -7/9
From the calculation, we can see that Bryce is wrong in step 1 because he did not distribute 3 over 5/3 thereby making his solution incorrect