Answer:
Both expressions are = to 11 when x is 2.
Therefore, the expressions are equivalent.
To find the hypotenuse of a right triangle you can use the Pythagorean theorem. (a² + b² = c²) Using the measurements provided we can solve like this.
Both a² & b² = 7²
7 x 7 = 49
49 + 49 = 98
Now we need to find the square root of 98 (c²) to get our answer.
9.9 x 9.9 = 98.01 or about 98
The measurements for the tirangle are 7 units, 7 units, and 9.9 units.
Hope this helps!
Answer:
everything is in the picture
Answer:
x = 0 , -2 , 1 +i√3 ; 1 - i√3
Step-by-step explanation:
2x⁴ + 16x = 0
2x(x³ + 8) = 0
2x(x³ + 2³) = 0
2x (x + 2)(x² -2x + 2²) = 0 {a³ + b³ = (a + b)*(a² -ab +b²}
2x = 0
x = 0
x + 2 = 0
x = -2
x² - 2x + 4 = 0
a = 1 ; b = -2 and c = 4
D = b² - 4ac = (-2)² - 4*1*4= 4 - 16 = -12

root = (-b ± √D)/2a
= (-(-2) ± 2i√3)/2*1
= (2 ± 2i√2)/2
