Ask question

Ask question

All categories

3 years ago

5

PLS HELP , I GOT ONLY ONE RIGHT AND THE REST ARE WRONG. I dont know what to do anymore pls help , its due todayyy plsjnn

1 answer:

Eva8 [605]3 years ago

6 0

So, you already know that angle CBD is 68 degrees, and the complementary angle to angle CBD is angle CBA. These angles together make 180 degrees because segment DBA is a straight line consisting of angles CBD and CBA. 180-68(the angle you already know) is 112 degrees for angle CBA. Then you repeat this process to find the other angles

You might be interested in

During the month of February, Fabulous Feet Shoe Mart sold 30 pairs of red loafers. After an ad campaign to boost sales, they so

blagie [28]

20%

20% of 30 =6
30+6 = 36

6 0

3 years ago

Read 2 more answers

What fraction represents the sum of 1/5 + 1/5 + 1/5

Drupady [299]

Answer:

0.6=6/10=3/5

Step-by-step explanation:

0.2+0.2+0.2

0.6

The tenth place wich means 6/10

Simplify by which gives you 3/5

6 0

3 years ago

Whats the anwser of 121p - 44

IRISSAK [1]

I think it would be 77p... It might not be but i think it is

4 0

3 years ago

Read 2 more answers

5.8 times<br> 9.3 times<br> 7.5 times<br> 12.1 times

Ber [7]

Answer:

7.5 times

Step-by-step explanation:

(1.86 * 10^5)/(2.48 * 10^4) = 7.5

4 0

3 years ago

Explain why f(x) = x^2-x-6/x^2-9 is not continuous at x = 3.

iren [92.7K]

Answer:

See Explanation

Step-by-step explanation:

Given

$f(x) = \frac{x^2 - x -6}{x^2 - 9}$

Required

Why is the function not continuous at x = 3

First substitute 3 for x at the denominator

$f(x) = \frac{x^2 - x -6}{x^2 - 9}$

Factorize the numerator and the denominator

$f(x) = \frac{x^2 - 3x+2x -6}{x^2 - 3^2}$

$f(x) = \frac{x(x - 3)+2(x -3)}{(x - 3)(x+3)}$

$f(x) = \frac{(x+2)(x - 3)}{(x - 3)(x+3)}$

Divide the numerator and denominator by (x - 3)

$f(x) = \frac{x+2}{x+3}$

Substitute 3 for x

$f(3) = \frac{3+2}{3+3}$

$f(3) = \frac{5}{6}$

<em>Because </em> $f(x) = \frac{x^2 - x -6}{x^2 - 9}$ <em> is defined when x = 3;</em>

<em>Then the function is continuous</em>

8 0

3 years ago