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mamaluj [8]
3 years ago
11

How do I explain? I don't get how

Mathematics
2 answers:
Alika [10]3 years ago
8 0
You should show part A to get better results from others because I think the information there is key to solving part B
Murljashka [212]3 years ago
7 0
Kiddo, you didn't draw the model that why
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What is the length of the hypotenuse of the triangle below? It’s D bro just took it
Viktor [21]

Answer: D

Step-by-step explanation:

a^2 +b^2 = c^2

3\sqrt{2}^2= 18

3\sqrt{2}^2= 18

18 + 18 = 36

The square root of 36 is 6

4 0
3 years ago
Read 2 more answers
find h and k such that the equation 3x^2 -hx +4k =0, so that the sum of the solutions is -12 and the product of the solutions is
Radda [10]
Let the solutions be a and b.
a = -2; b = -10
a + b = -2 + (-10) = -12
ab = (-2)(-10) = 20

(x - a)(x - b) = 0

(x - (-2))(x - (-10)) = 0

(x + 2)(x + 10) = 0

x^2 + 10x + 2x + 20 = 0

x^2 + 12x + 20 = 0

-h = 12

h = -12

4k = 20

k = 5
6 0
3 years ago
I need help please?!!!!!!
Sindrei [870]

Answer:

-2x-10 ≥ 22

Collect like terms

-2x ≥ 22+10

-2x ≥ 32

divide both sides by -2

x ≥ -16.

5 0
3 years ago
What is the best approximation for the input value when f(x)=g(x)?
Lostsunrise [7]

Answer:

x=0 and x=1.

Step-by-step explanation:

If we have to different functions like the ones attached, one is a parabolic function and the other is a radical function. To know where f(x)=g(x), we just have to equalize them and find the solution for that equation:

x^{2}=\sqrt{x} \\(x^{2} )^{2}=(\sqrt{x} )^{2}\\x^{4}=x\\x^{4}-x=0\\x(x^{3}-1)=0\\

So, applying the zero product property, we have:

x=0\\x^{3}-1=0\\x^{3}=1\\x=\sqrt[3]{1}=1

Therefore, these two solutions mean that there are two points where both functions are equal, that is, when x=0 and x=1.

So, the input values are  x=0 and x=1.

8 0
3 years ago
Read 2 more answers
A ferris wheel can accommodate 54 people in 24 minutes. How many people could ride the ferris wheel in 2 hours? What was that ra
Vladimir79 [104]
120÷24=5

5×54=270

270 People in 2 hours
3 0
3 years ago
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