Answer: D
Step-by-step explanation:
a^2 +b^2 = c^2
= 18
3\sqrt{2}^2= 18
18 + 18 = 36
The square root of 36 is 6
Let the solutions be a and b.
a = -2; b = -10
a + b = -2 + (-10) = -12
ab = (-2)(-10) = 20
(x - a)(x - b) = 0
(x - (-2))(x - (-10)) = 0
(x + 2)(x + 10) = 0
x^2 + 10x + 2x + 20 = 0
x^2 + 12x + 20 = 0
-h = 12
h = -12
4k = 20
k = 5
Answer:
and
.
Step-by-step explanation:
If we have to different functions like the ones attached, one is a parabolic function and the other is a radical function. To know where
, we just have to equalize them and find the solution for that equation:

So, applying the zero product property, we have:
![x=0\\x^{3}-1=0\\x^{3}=1\\x=\sqrt[3]{1}=1](https://tex.z-dn.net/?f=x%3D0%5C%5Cx%5E%7B3%7D-1%3D0%5C%5Cx%5E%7B3%7D%3D1%5C%5Cx%3D%5Csqrt%5B3%5D%7B1%7D%3D1)
Therefore, these two solutions mean that there are two points where both functions are equal, that is, when
and
.
So, the input values are
and
.