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Answer:
The formula that can be used to describe the given sequence is
Step-by-step explanation:
Given : sequence -4, −24, −144,...
We have to find the formula that can be used to describe the given sequence -4, −24, −144,...
A geometric sequence is a sequence in which each higher term is multiplied by a constant number called common ratio.
Written as a, ar , ar², ar³., ....
and general term is calculated as
Where a is first term and r is common ratio.
Consider the given sequence -4, −24, −144,...
We find the common ratio ,
Thus, common ratio is given as
Thus, the given sequence is a geometric sequence.
The general term is given by
Put a = -4 , r = 6
We have
Thus, the formula that can be used to describe the given sequence is
A1) One possible set of inequalities is
x +y > 2
y -x < 4
A2) The lines are graphed as though the inequality were an equal sign. Since the inequality does not include the "or equal to" case, the lines are drawn dashed. In each case, the area to the right of the line is shaded.
B) Points A and B are solutions to the system if they are in the doubly-shaded region (which they are). In the graph here, that region is darker orange. (For this purpose, you need to ignore the green region, which overlaps part of the solution space.
C) The houses Billy is interested in are found by graphing the inequality and identifying the houses in its solution space. (Those houses are B and C.) Alternatively, you can evaluate the inequality for each of the house coordinates and see which ones give "true."
x +y > 2
y -x < 4
A2) The lines are graphed as though the inequality were an equal sign. Since the inequality does not include the "or equal to" case, the lines are drawn dashed. In each case, the area to the right of the line is shaded.
B) Points A and B are solutions to the system if they are in the doubly-shaded region (which they are). In the graph here, that region is darker orange. (For this purpose, you need to ignore the green region, which overlaps part of the solution space.
C) The houses Billy is interested in are found by graphing the inequality and identifying the houses in its solution space. (Those houses are B and C.) Alternatively, you can evaluate the inequality for each of the house coordinates and see which ones give "true."