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ipn [44]
3 years ago
8

F(x) = x^2. What is g(x)?

Mathematics
1 answer:
ladessa [460]3 years ago
4 0

Answer:

-x²-2

Step-by-step explanation:

x² = the curve faces upwards

but

-x² the curve faces downwards.

also

the downward curve touches -2 on the y axis.

therefore gx = -x²-2

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25+25= so first u want to add 5+5so that equals 10 so u put the one on the top of 2 then u add2+2+1 so that equals 5 so ur answe
goblinko [34]

Answer:

So you pretty much just solved your math by yourself :)

Step-by-step explanation:

7 0
3 years ago
Help me with number 2,3,4,5 please
nlexa [21]
This site may help you

http://www.cpalms.org/Public/PreviewResourceAssessment/Preview/65260

1. 4y – y and 4 because “4y – y = 4.”
not equivalent because we don't know what y is

2.not equivalent
2x + 7x and 9x because “5 + 3 = 8.”
7 0
4 years ago
Read 2 more answers
At the stadium, the Grandstands, Bleachers and Box Seats cost $6.75, $4.50 and $10.50, respectively. If you have $80, then how m
Vesna [10]
You would be able to buy 7 seats because you would divide 10.50 by 80 and you would get 7.6.... and you don't have a 6th of a person so it would then be just 7. 
7 0
4 years ago
Algebra homework packet answer for 50 points.
Bingel [31]
The standard form for a parabola is (x - h)2 = 4p (y - k), where the focus is (h, k + p) and the directrix is y = k - p. If the parabola is rotated so that its vertex is (h,k) and its axis of symmetry is parallel to the x-axis, it has an equation of (y - k)2 = 4p (x - h), where the focus is (h + p, k) and the directrix (d)
is x = h - p.
So directrix is: y = k - p and the focus is at:
(h, k+p)
Since our focus is: (1, 3) and directrix is: y = 1,
thus h = 1, k+p = 3, and k-p = 1
Therefore k = 3-p, 3-p-p = 1, k = 3-p = 3-1 = 2
3-2p = 1, -2p = -3+1, -2p = -2, p = 1
Now we plug p, k, & h into standard form:
(x - h)2 = 4p (y - k)
{(x - 1)}^{2}  = 4(1)(y - 2) \\  {(x - 1)}^{2}  = 4y - 8 \\ 4y =  {(x - 1)}^{2}  + 8 \\ y =  ({(x - 1)}^{2} \div 4) + 2
y = 1/4 (x-1)^2 + 2



5 0
4 years ago
What is a quartic function with only two real zeros at x = 7 and x = 13
Fittoniya [83]

Zeros be a and b

  • a=7
  • b=13

Function

\\ \sf\longmapsto y=x^2-(a+b)x+ab

\\ \sf\longmapsto y=x^2-(7+13)x+(7)(13)

\\ \sf\longmapsto y=x^2-20x+91

Option B

3 0
3 years ago
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