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Brrunno [24]
2 years ago
13

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Mathematics
2 answers:
Olegator [25]2 years ago
8 0

Answer:

Thanks.......... follow me

IRINA_888 [86]2 years ago
8 0

Answer:

please go help me with my 4 most recent questions please!!

Step-by-step explanation:

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What is the soulution set of the equation 3x^2=48
valentina_108 [34]

Answer:

x = ± 4

Step-by-step explanation:

given 3x² = 48 ( divide both sides by 3 )

x² = 16 ( take the square root of both sides )

x = ± \sqrt{16} = ± 4

x ∈ {- 4, 4 }


8 0
3 years ago
Read 2 more answers
(PLEASE ANSWER + BRAINLIEST ANSWER!!)
murzikaleks [220]

The arc length, radius and the included angle are related as

r\theta=\widehat {XYZ} where \theta is in radians.

The radius r is given by

r=\frac{\widehat {XYZ} }{\theta} \\ r=\frac{10.8}{1.8} \\ r=6\;units

Correct choice is (B).

8 0
3 years ago
Read 2 more answers
Triangle ABC is similar to triangle XYZ. Which proportion can be used to find the measure of the missing side?
lisov135 [29]
I'm not sure what side is missing but you could use the proportions

A/B=X/Y or B/C=Y/Z or CA/=ZX. it also works if you reverse this for example B/A=Y/X


7 0
3 years ago
Read 2 more answers
15 Points!
Nezavi [6.7K]
Replace f(x) with 0 and swith the equation around to solve for x

 x^4 - 32x^2 - 144 = 0

Factor the left side:

(x+6) (x-6) (x^2+4)

so far we have x+6 = 0, x = -6
                         x -6 = 0, x = 6

solve x^2 +4 = 0
x^2 = -4
x = sqrt(-4) 
x = 2i, -21

The answer is B) 2i, 6, -6
8 0
3 years ago
Read 2 more answers
Find all solutions and solutions in interval[0,2pi)
frutty [35]
\bf sin(2\theta)=2sin(\theta)cos(\theta)\\\\
-------------------------------\\\\
sin(2x)-\sqrt{3}cos(x)=0\implies 2sin(x)cos(x)-cos(x)\sqrt{3}=0
\\\\\\
\stackrel{\stackrel{common}{factor}}{cos(x)}[2sin(x)-\sqrt{3}]=0\\\\
-------------------------------\\\\

\bf cos(x)=0\implies \measuredangle x=
\begin{cases}
\frac{\pi }{2}\\\\
\frac{3\pi }{2}
\end{cases}\\\\
-------------------------------\\\\
2sin(x)-\sqrt{3}=0\implies 2sin(x)=\sqrt{3}\implies sin(x)=\cfrac{\sqrt{3}}{2}
\\\\\\
\measuredangle x=
\begin{cases}
\frac{\pi }{3}\\\\ \frac{2\pi }{3}
\end{cases}
7 0
3 years ago
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