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tino4ka555 [31]
4 years ago
11

PLEASE HELP 23-(-10÷2+6)+(-13)

Mathematics
2 answers:
Nataly [62]4 years ago
6 0

Answer:

=9

Step-by-step explanation:

SOVA2 [1]4 years ago
3 0

Answer:

9

Step-by-step explanation:

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Your sister starts a new business selling iced tea. She borrowed money from you for the initial supplies, which cost a total of
Ivenika [448]

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Question 1 - she will make $10.50 and still owe you $5.25 because 0.35 x 30 = 10.25

question 2 - for this im not sure because the 2nd, 3rd and 4th wont work so it should be the first but I’m not sure what that equation is saying

question 3 - 29 glasses need to be sold

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3 years ago
HELP PLEASE IT IS DUE TODAY!!!!!!!!!!!!! Please <br> It is 1-5 please answer 1-5
tatyana61 [14]

Multiple and add

Step-by-step explanation:

For all of them you multiple 1 and add the inherent that's what area and perimter means

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3 years ago
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What is the sum of 1/8+5/15+3/8​
Ymorist [56]

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pls give me brainliest

Step-by-step explanation:

0.83333333333

8 0
3 years ago
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A random sample of 60 mathematics majors spent an average of $200.00 for textbooks for a term, with a standard deviation of $22.
tangare [24]

Answer:

20 +/- $6.74

= ( $13.26, $26.74)

The 90% confidence interval for the difference in average amounts spent on textbooks (math majors - English majors) is ( $13.26, $26.74)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x1-x2 +/- margin of error

x1-x2 +/- z(√(r1^2/n1 + r2^2/n2)

Given that;

Mean x1 = $200

x2 = $180

Standard deviation r1 = $22.50

r2 = $18.30

Number of samples n1 = 60

n2 = 40

Confidence interval = 90%

z(at 90% confidence) = 1.645

Substituting the values we have;

$200-$180 +/-1.645(√(22.5^2/60 +18.3^2/40)

$20 +/- 6.744449847374

$20 +/- $6.74

= ( $13.26, $26.74)

The 90% confidence interval for the difference in average amounts spent on textbooks (math majors - English majors) is ( $13.26, $26.74)

3 0
3 years ago
In 2009, a tree was 10 feet tall. In 2012, the tree was 16 feet tall. Construct a linear model that represents the height, h, of
HACTEHA [7]

Answer:

h = 2t + 4

Step-by-step explanation:

Solution:-

- The height of the tree = h

- The number of years elapsed after 2006 = t

- height h1 = 10 ft, t1 = ( 2009 - 2006 ) = 3 yrs

- height h2 = 16 ft, t2 = ( 2012 - 2006 ) = 6 years

- The linear model of tree height "h" as a function of time "t" years after 2006 can be expressed in the form:

                           h = m*t + c

Where,               m = The rate of change of height

                          c = The initial height of tree in 2006.

- We will use the given data to evaluate constant "m".

                         Rate =  m = ( h2 - h1 ) / ( t2 - t1)

                         m = ( 16 - 10 ) / ( 6 - 3 )

                         m = 6 / 3 = 2

-  Then use "m" and given set of data to evaluate the initial height of tree "c" in year 2006.

                          h = 2*t + c

                          h1 = 2*t1 + c

                          c = 10 - 2*3 = 4 ft

- The linear model for the height of tree "h" as fucntion of time "t" years after 2006 will be:

                          h = 2t + 4

8 0
3 years ago
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