Question

In a certain residential suburb, 60% of all households get Internet service from the local cable company, 80% get television service from that company, and 50% get both services from that company. Select a household at random. Use three decimals. a.) What is the probability that it gets at least one of these two services from the company? Lethousehold with Internet service H teens = H2 What is the probability that t gets enactly one of these services from probability that it gets exactly one of these services from the company?

Answer 1

Answer:

a) 0.900

b) 0.400

Step-by-step explanation:

Let I = households getting internet

T = households getting television

Then I = 60%

and T = 80%

$I\cap T = 50\%$ (Households that get both services)

a) Households getting at least one service, $I\cup T = I + T - I\cap T= 60+80-50 =90\%=0.900$

b) Those getting internet only = $I - I\cap T = 60 - 50 = 10\% = 0.1$

Those getting television only = $T - I\cap T = 80- 50=30\%=0.3$

Probability of getting exactly one service = 0.1 + 0.3 = 0.400