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4 years ago

What is the simplest form of 5 3/6

Mathematics

2 answers:

IRINA_888 [86]4 years ago

7 0

Mixed number fraction5 1/2 or Improper fraction 11/2

BabaBlast [244]4 years ago

6 0

Blahhhhhhh blah blahhhhhhhhhh go ask your teacher for some help. I'm sure they would be glad to ;)

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Given the venn diagram, find P(brother and sister)

LUCKY_DIMON [66]

Based on the venn diagram of siblings, the probability of having a brother and sister is c. 0.33.

<h3>What is the probability of brother and sister?</h3>

The probability of having a brother and sister can be found as:

= Number of those with brother and sister / Total number of people in poll

Solving gives:

= 10 / (8 + 10 + 5 + 7)

= 10 / 30

= 0.33

In conclusion, the probability of having a brother and sister is 0.33.

Find out more on Venn diagrams at brainly.com/question/9085273

#SPJ1

6 0

2 years ago

Completing the square:

vichka [17]

Answer:

Step-by-step explanation:

Key to this method is remembering that

$(a+b)^2 = a^2 + 2ab + b^2$

So, if you divide the coefficient of x by 2 and square it, that will complete the square. With that in mind, things are easy.

6/2 = 3, so add $3^2 = 9$

$x^2+6x+9 = (x+3)^2$

So, c=9

Similarly, for the other two,

$c = (\frac{-34}{2} )^2 = (-17)^2 = 289$

You don't really have to worry about the sign, since squaring will always make it positive

$(\frac{25}{13}) ^2 = \frac{625}{169}$

7 0

4 years ago

Paint is red : blue in a ratio 2:4. if 6 litres of blue is used how much red

butalik [34]

Red=2 nits
blue=4 nits

if 6liters=blue=4 units
divide 2
3 liters=2 units=red

red=3 liters

6 0

3 years ago

1. tan a = cot(a + 10°)

Temka [501]

Answer:

$a=40+90n$

Step-by-step explanation:

Use a cofunction identity on the right hand side or left hand side...

So $\tan(a)=\cot(90-a)$ .

We have the equation:

$\tan(a)=\cot(a+10)$

Make the above replacement:

$\cot(90-a)=\cot(a+10)$

Since cotangent has period 180 degrees, we can also write this as:

$\cot(90-a+180n)=\cot(a+10)$

So solving the following will give us a set of solutions for $a$ :

$90-a+180n=a+10$

Add $a$ on both sides:

$90+180n=2a+10$

Subtract 10 on both sides:

$80+180n=2a$

Divide both sides by 2:

$40+90n=a$

Symmetric property:

$a=40+90n$

7 0

3 years ago

Can anyone figure this out?

Verizon [17]

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10})\qquad A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NA=\sqrt{(6+3)^2+(3-10)^2}\implies NA=\sqrt{130} \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1}) \\\\\\ AD=\sqrt{(6-6)^2+(-1-3)^2}\implies AD=4 \\\\[-0.35em] ~\dotfill$

$\bf D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1})\qquad N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10}) \\\\\\ DN=\sqrt{(-3-6)^2+(10+1)^2}\implies DN=\sqrt{202}$

now that we know how long each one is, let's plug those in Heron's Area formula.

$\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{130}\\ b=4\\ c=\sqrt{202}\\[1em] s=\frac{\sqrt{130}+4+\sqrt{202}}{2}\\[1em] s\approx 14.81 \end{cases} \\\\\\ A=\sqrt{14.81(14.81-\sqrt{130})(14.81-4)(14.81-\sqrt{202})} \\\\\\ A=\sqrt{324}\implies A=18$

5 0

4 years ago