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Lady_Fox [76]
3 years ago
13

A builder cuts a rectangular hole in a ceiling to install an exhaust fan. The width is 3 in. less than the length and the area i

s 180 in². Find the length and width of the hole.
Mathematics
1 answer:
slavikrds [6]3 years ago
8 0

Area of a rectangle = l * w

A = Area of a rectangle

l = length

w = width

In our problem,

l = x

w = x - 3

A = 180 square inches

Plug our numbers into the area formula of a rectangle

180 square inches = x(x-3)

Distribute the x into (x-3)

180 square inches = x^2 - 3x

subtract 180 from both sides

0 = x^2 - 3x -180.

Factor the express on the left side of the equation

0 = (x-15) (x+12).

Set each term equal to zero and solve for x

x+12 = 0.

Subtract 12 from both sides

x = -12 <--- lengths of a rectangle cannot be negative, therefore, we need to check the other term we factored.

set x-15 equal to zero

x-15 = 0.

Add 15 to both sides

x = 15.

We know l = x so now we know that the length i = 15 inches.

We also know that the width = length - 3

w = 15 - 3

w = 12

The width is 12 inches and the length is 15 inches

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Marizza181 [45]

Hey there!

<h2>ANSWER: </h2>

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Fill in the blank.<br> (5x)2<br> a0x2
Yuki888 [10]

Answer:a_0=25

Step-by-step explanation:

It is given that, (5x)^2=a_0x^2

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Solving LHS

25x^2=a_0x^2

Now comparing the coefficients of x^2

In LHS the coefficient of x^2 is 25

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5 0
3 years ago
Which equation is in point-slope form and depicts the equation of this line?
Elodia [21]
We know
in the graph two points
point 1 (2,1)  and point 2 (-1,-4)
the equation in point-slope form is ----------------> (y-y1)=m(x-x1)

step 1
find the value of m
m=(y2-y1)/(x2-x1)----------> (-4-1)/(-1-2)--------> m=5/3

step 2
with the point (-1,-4)  and m=5/3
find the equation in point-slope form
(y-(-4))=(5/3)*(x-(-1))-------------> (y+4)=(5/3)(x+1)

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Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (
Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

P(\frac{T}{S}) = 0.95

P(\frac{T}{S^c}) = 0.05

Now based on the above information, the probabilities are as follows

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= P(S)

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ii. P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}

= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }

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= 0.8906

iii. P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}

= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }

= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}

= 0.0221

We simply applied the above formulas so that the each part could come

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