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Helen [10]
3 years ago
8

*PLEASE HELP WILL GIVE BRAINLIEST ANSWER* Which expression is NOTA equivalent to -2/5(3-3/4)?

Mathematics
1 answer:
Leya [2.2K]3 years ago
6 0

the answer is c plz can I have brainliest please I'm new

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One dozen bananas weigh 3 pounds, how much do 2 bananas weigh?
pantera1 [17]

Answer: 50

Step-by-step explanation: If a dozen is 3 pounds then half a dozen would 6 which should be 1.50 lb. Now we need to know how much 1 banana weights. lets add all twelve until we have 3 pounds. 12 x 25 = 300 or 3.00 lb so we now know 2 bananas weight 50.

3 0
3 years ago
Read 2 more answers
Need help on solving this ?
katovenus [111]
For the first question, simply plug in the value of 3 into the polynomial question. The final answer is your volume of the hot water tub.

For the second question, you can figure out that x = -5 is not a real root because it does not touch or cross the x axis.

If it does it would be an solution.





4 0
3 years ago
In the derivation of Newton’s method, to determine the formula for xi+1, the function f(x) is approximated using a first-order T
dimaraw [331]

Answer:

Part A.

Let f(x) = 0;

suppose x= a+h

such that f(x) =f(a+h) = 0

By second order Taylor approximation, we get

f(a) + hf'±(a) + \frac{h^{2} }{2!}f''(a) = 0

h = \frac{-f'(a) }{f''(a)} ± \frac{\sqrt[]{(f'(a))^{2}-2f(a)f''(a) } }{f''(a)}

So, we get the succeeding equation for Newton's method as

x_{i+1} = x_{i} + \frac{1}{f''x_{i}}  [-f'(x_{i}) ± \sqrt{f(x_{i})^{2}-2fx_{i}f''x_{i} } ]

Part B.

It is evident that Newton's method fails in two cases, as:

1.  if f''(x) = 0

2. if f'(x)² is less than 2f(x)f''(x)    

Part C.

In case  x_{i+1} is close to x_{i}, the choice that shouldbe made instead of ± in part A is:

f'(x) = \sqrt{f'(x)^{2} - 2f(x)f''(x)}  ⇔ x_{i+1} = x_{i}

Part D.

As given x_{i+1} = x_{i} = h

or                 h = x_{i+1} - x_{i}

We get,

f(a) + hf'(a) +(h²/2)f''(a) = 0

or h² = -hf(a)/f'(a)

Also,             (x_{i+1}-x_{i})² = -(x_{i+1}-x_{i})(f(x_{i})/f'(x_{i}))

So,                f(a) + hf'(a) - (f''(a)/2)(hf(a)/f'(a)) = 0

It becomes   h = -f(a)/f'(a) + (h/2)[f''(a)f(a)/(f(a))²]

Also,             x_{i+1} = x_{i} -f(x_{i})/f'(x_{i}) + [(x_{i+1} - x_{i})f''(x_{i})f(x_{i})]/[2(f'(x_{i}))²]

6 0
3 years ago
Pls answer professionally or with the right answer I’m beg you
Crazy boy [7]
1) y=106 x=106 2) z=68 y=112 x=112
3 0
3 years ago
Read 2 more answers
If it takes 1/2 day to write a report, how much will be completed after 1/4 of a day?
lana [24]

Answer:

You have completed only half in a 1/4 of a day

Step-by-step explanation:

think of it this way

lets say in half a day e.g at 12pm you finish the report

half of 12 is 6

so that would be a 1/4 of the day

100%=24 hours=whole day

50%=12 hours=half a day

25%=6 hours = quarter of a day

25% = 1/4

i hope this helps

7 0
3 years ago
Read 2 more answers
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