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BartSMP [9]
3 years ago
8

ALGEBRA

Mathematics
2 answers:
sweet [91]3 years ago
7 0
The final bill is $544
The parts is a one time bill of $265
The labor is $48 per hour, and lets call the hours 'h'

So we can make the equation as:

544 = 265 + 48h

Subtract 265 n both sides

279 = 48h

Divide by 48 on both sides

h = <span>5.8125

So the number of hours of labor spent repairing the car is </span><span>5.8125.</span>
AnnZ [28]3 years ago
3 0
The equation would be
544 = 265 + 48x

The first step is to subtract 265 from both sides.
279 = 48x

The next step is to divide by 48 on both sides.
x=5.8125

That means that the mechanic worked for 5.8125 hours.
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the length of a rectangle is 6in.more than than its width .Its area is 50 sq.in Find the width of the rectangle....
yulyashka [42]
L=6+W
A=LW
sub 6+W for L
A=(6+W)(W)
expand
oh, A=50
50=W²+6W
minus 50 both sides
0=W²+6W-50
we gots to use quadratic formula
for
aW²+bW+c=0
W=\frac{-b+/- \sqrt{b^2-4ac} }{2a}
we got
a=1
b=6
c=-50


W=\frac{-(6)+/- \sqrt{(6)^2-4(1)(-50)} }{2(1)}
W=\frac{-6+/- \sqrt{36+200} }{2}
W=\frac{-6+/- \sqrt{236} }{2}
W=\frac{-6+/- 2\sqrt{59} }{2}
W=-3+/- \sqrt{59}

W=-3+ \sqrt{59} or W=-3- \sqrt{59}
aprox
W=-10.6811 or W=4.68115
can't be negative width

width=4.68115 or -3√59
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