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stellarik [79]
3 years ago
15

Nala and lily are playing a dice game where they score points. After one round, the ratio of nala point to lily's point is 7 to

9. If nala has 14 more points than lily, determine how many points lily has.
Mathematics
1 answer:
Kazeer [188]3 years ago
7 0

Answer:

Lily has 63 points and Nala has 49.

Step-by-step explanation:

Since Nala and Lily are playing a dice game where they score points, and after one round, the ratio of Nala's points to Lily's points is 7 to 9, if Nala has 14 more points than Lily, to determine how many points Lily has se you must perform the following calculation:

9 - 7 = 2

14/2 = 7

7 x 7 = 49

7 x 9 = 63

63 - 49 = 14

Therefore, Lily has 63 points and Nala has 49.

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3 years ago
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3 years ago
What is the length of the shadow cast by a 12-foot lamp post when the angle of elevation of the sun is 60º? (to the nearest tent
elena-s [515]

Answer:

6.9 foot.

Step-by-step explanation:

Given: Length of lamp post= 12-foot.

           The angle of elevation of the sun is 60°.

∴ The length of Lamp post, which is opposite is 12-foot.

  Now, finding the length of shadow cast by foot lamp.

Length of shadow is adjacent.

∴ We know the formula for Tan\theta= \frac{Opposite}{adjacent}

Next, putting the value in the formula.

⇒ Tan 60° = \frac{12}{adjacent}

Cross multiplying both side and using the value of Tan 60°

∴ Adjacent= \frac{12}{\sqrt{3} } = 6.92 ≅ 6.9 (nearest tenth value)

6.9 is the length of shadow cast by a 12-foot lamp post.

3 0
3 years ago
Answer ASAP!
valentinak56 [21]

Answer:

A and D

Step-by-step explanation:

Since tangent is opposite/adjacent,

Tan 40 in this case would be x/3.8 (i used x because we don't know what the value is)

So, you set it up as an algebra problem

Tan40 = x/3.8

Multiply both sides by 3.8

3.8tan40 = x, Option A

And then, angle E is 50 degrees

So tan 50 = 3.8/x

Multiply both sides by x

tan50x = 3.8

Divide both sides by tan50

x= 3.8/tan50

So, A and D are both correct

3 0
2 years ago
A farmer has a truckload of watermelons to take to market. At the beginning of the trip, the watermelons weigh 1000 kg. 99% of t
Mariulka [41]

Answer:

The weight of watermelon at the end of the trip is <u>500 kg.</u>

Step-by-step explanation:

Given:

The weight of watermelons is 1000kg.

At the beginning of the trip watermelon is 99% of the weight:

99% of 1000kg

\frac{99}{100}\times 1000

=0.99\times 1000

= 990 kg

Now, at the end of the trip it is 98% of weight. So, let x kg of water has been evaporated. So, remaining weight of the watermelon is 1000-x.

If x kg of water is removed, then the amount of water left is 990-x.

As per question, water now weighs 98% of the total weight. So,

98% of (1000-x) = 990-x

\frac{98}{100}\times (1000-x)=990-x

980-0.98x=990-x

-0.98x+x=990-980 (Bringing like terms on one side)

0.02x=10\\x=\frac{10}{0.02}=500\ kg

Therefore, the weight of watermelon at the end of the trip is given as:

Weight = 1000 - x = 1000 - 500 = 500 kg

Therefore, the watermelon weighs 500 kg at the end of trip.

7 0
3 years ago
Read 2 more answers
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