Answer:
w=p/2-t
Step-by-step explanation:
Let the second car meets the first car after n hours.
Second car starts with 8km/h, After succeeding hours his speed increases by 0.5 km.
So, Distance travelled by second car = 8 + 8.5 + 9
..... 8+(n-1) 0.5.....(1)
eqn. (1) sum of n terms Of A.P with first term 8
and common difference 0.5.
Sum of all the terms in equation 1 is also equals to the distance travelled by the first car for n hours, i.e. 10n km .
Now, we have (n/2) {16+(n-1) 0.5} = 10n........(2)
From equation (2) we get, n= 9
Hence, Both the cars will meet after 9 hours.
Hope it helps!
2x+6 is the base
Then the equation is logarithm of 144 on basis 2x + 6 = 2
Then [2x + 6]^2 = 144
Now expand the square binomial
4x^2 + 24x + 36 = 144
4x^2 + 24x + 36 - 144 = 0
4x^2 + 24x - 108 = 0
Divide by 4
x^2 + 6x - 27 = 0
Factor: (x + 9 ) (x - 3) = 0
x = -9 and x = 3
The only valid is x = 3, because x = -9 yields 2x + 6 = - 12 and the logarithm function cannot have negative basis.
Then the answer is x = 3.
Answer:
No, I don't think so.
Step-by-step explanation:
If his suitcase weighs 23 kg and 10 kg is 22 pounds. You could seperate it. 10, 10, and 3 meaning 22+22= 44. This would mean that 1 kg would equal about 2.2 a pound. So 44 + ( 2.2 x 3 ) = 50.6 kg.
It would be 0.6 k.g over. I think this is right unless I calculated this wrong.
